The figure below represents a play space that Logan fenced in for his dog.
1 answer:
Answer:
Difference in area = 75 ft²
Step-by-step explanation:
Case 1 (When logan had only one dog):
length of the play space= ft
breadth of the play space= ft
we know that area of a rectangle is length times breadth (length x breadth)
therefore, area of the play space=
=
Case 2(When Logan had two dogs):
Given: Logan wants to increase the length of the play space by 3 feet and width by 3 feet
⇒length of the play space= ft=
ft
breadth of the play space= ft=
ft
we know that area of a rectangle is length times breadth (length x breadth)
therefore, area of the play space=
=
Therefore difference in the area of play space =
=75 ft²
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Answer:
Table is attached with values, but answers are:
(0, 0) (1, 3) (2, 6) (3, 9)
Step-by-step explanation:
y = 3x
Substitute all values.
y = 3(0)
y = 0
0, 0
y = 3(1)
y = 3
1, 3
y = 3(2)
y = 6
2, 6
y = 3(3)
y = 9
3, 9
