Question

The figure below represents a play space that Logan fenced in for his dog.

Answer 1

Answer:

Difference in area = 75 ft²

Step-by-step explanation:

Case 1 (When logan had only  one dog):

length of the play space= $12$ ft

breadth of the play space= $10$ ft

we know that area of a rectangle is length times breadth (length x breadth)

therefore, area of the play space= $12*10$

                                                      =$120ft^{2}$

Case 2(When Logan had two dogs):

Given: Logan wants to increase the length of the play space by 3 feet  and width by 3 feet

⇒length of the play space= $12+3$ ft=$15$ ft

breadth of the play space=$10+3$ ft=$13$ ft

we know that area of a rectangle is length times breadth (length x breadth)

therefore, area of the play space= $15*13$

                                                      =$195ft^{2}$

Therefore difference in the area of play space = $195-120$

                                                                                =75 ft²