Answer:
GH
Step-by-step explanation:
![\rm 5=e^{3b}](https://tex.z-dn.net/?f=%5Crm%205%3De%5E%7B3b%7D)
The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.
We'll take log of each side.
Log of what base tho?
Well, the base of our exponential is e,
so we'll take log base e of each side.
![\rm log_e(5)=log_e(e^{3b})](https://tex.z-dn.net/?f=%5Crm%20log_e%285%29%3Dlog_e%28e%5E%7B3b%7D%29)
We'll apply one of our log rules next:
![\rm \log(x^y)=y\cdot\log(x)](https://tex.z-dn.net/?f=%5Crm%20%5Clog%28x%5Ey%29%3Dy%5Ccdot%5Clog%28x%29)
This allows us to take the exponent out of the log,
![\rm log_e(5)=(3b)log_e(e)](https://tex.z-dn.net/?f=%5Crm%20log_e%285%29%3D%283b%29log_e%28e%29)
Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
![\rm log_{10}(10)=1](https://tex.z-dn.net/?f=%5Crm%20log_%7B10%7D%2810%29%3D1)
![\rm log_5(5)=1](https://tex.z-dn.net/?f=%5Crm%20log_5%285%29%3D1)
![\rm log_e(e)=1](https://tex.z-dn.net/?f=%5Crm%20log_e%28e%29%3D1)
So our equation simplifies to this,
![\rm log_e(5)=(3b)\cdot1](https://tex.z-dn.net/?f=%5Crm%20log_e%285%29%3D%283b%29%5Ccdot1)
As a final step, divide both sides by 3,
![\rm \frac13log_e(5)=b](https://tex.z-dn.net/?f=%5Crm%20%5Cfrac13log_e%285%29%3Db)
k, hope that helps!
Answer: 1
Step-by-step explanation:
From the given picture, it can be seen that there is a plane H on which two pints J and K are located.
One of the Axiom in Euclid's geometry says that <em>"Through any given two points X and Y, only one and only one line can be drawn "</em>
Therefore by Axiom in Euclid's geometry , for the given points J and K in plane H , only one line can be drawn through points J and K.
Answer:
i would say C. its probabaly a lucky guess ldk see if im correct and have a wonderful day :)
Step-by-step explanation: