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3 years ago

45+22 answer pls help

2 answers:

7 0

P.E.M.D.A.S

No Parenthesis and no Exponents, There is Multiplication

4 x 5 = 20
2 x 2 = 4

Now your problem looks like this: 20 + 4 = 24

Your answer is 24

Hope I helped :)

vekshin13 years ago

5 0

If your just adding and multiplying the answer is 44

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Vesna [10]

Helloo, i don’t see the image seen above, is that the only picture?

6 0

3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

3 years ago

Help! math, ill give u 20 points

Pepsi [2]

10
is the range of it

4 0

3 years ago

Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. How many different groups

irakobra [83]

Answer:

56 groups of 5 Fabergé eggs can be taken.

Step-by-step explanation:

It is given that Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. In order to find how many different groups of 5 Faberge' eggs can she take, we apply the combination formula:

$8C_{5}=\frac{8!}{5!(8-5)!}$

$8C_{5}=\frac{8!}{5!3!}$

$8C_{5}=\frac{8{\times}7{\times}6{\times}5!}{5!{\times}3{\times}2}$

$8C_{5}=56$

Thus, 56 groups of 5 Fabergé eggs can be taken.

8 0

3 years ago

a tea company surveyed shoppers at two different malls. shoppers were asked whether they prefer sweetened or unsweetened tea. at

FromTheMoon [43]

First, let's create the ratios of sweetened to unsweetened. To do this, you would have to subtract the number of people that preferred unsweetened from the total.
Westside mall: 15:30 or $\frac{15}{30}$
Eastside mall: 13:26 or $\frac{13}{26}$

Now, you would divide to both ratios.
15 ÷ 30 = 0.5
13 ÷ 26 = 0.5

They have the same sum, meaning, they are the same.

Westside Mall shoppers are just as likely to prefer unsweetened tea as Eastside Mall shoppers.

I hope this helps!

8 0

3 years ago

4*5+2*2 answer pls help

45+22 answer pls help