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3 years ago

45+22 answer pls help

2 answers:

7 0

P.E.M.D.A.S

No Parenthesis and no Exponents, There is Multiplication

4 x 5 = 20
2 x 2 = 4

Now your problem looks like this: 20 + 4 = 24

Your answer is 24

Hope I helped :)

vekshin13 years ago

5 0

If your just adding and multiplying the answer is 44

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Sahil got 28 questions right on the math test. Angelina got 7 more wrong answers than Sahil. There where 40 questions on the tes

Mariana [72]

[A+7= 28] is the correct equation I believe, though I may be wrong.

7 0

2 years ago

Read 2 more answers

Find the value of x so that the line passing through the points will have the given slope: (x,6) and (10,-3) with a slope of -3/

Lana71 [14]

$(x,6) \\
x_1=x \\
y_1=6 \\ \\
(10,-3) \\
x_2=10 \\ y_2=-3 \\ \\
\hbox{the slope: } m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3-6}{10-x}=\frac{-9}{10-x} \\ \\
m=-\frac{3}{2} \\
\Downarrow \\
-\frac{3}{2}=\frac{-9}{10-x} \\
-\frac{3}{2}(10-x)=-9 \\
10-x=-9 \times (-\frac{2}{3}) \\
10-x=3 \times 2 \\
10-x=6 \\
-x=6-10 \\
-x=-4 \\
\boxed{x=4}$

6 0

3 years ago

In ATUV, the measure of V=90°, TU = 5.4 feet, and VT = 1.6 feet. Find the measure

luda_lava [24]

Answer:73

Step-by-step explanation:

7 0

3 years ago

A test is used to assess readiness for college. In a recent year, the mean test score was 20.3 and the standard deviation was 4

Vlada [557]

Answer:

$\mu = 20.3$

$\sigma = 4.9$

And we can find the limits in order to consider values as significantly low and high like this:

$Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5$

$High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is higher tor equal to 2.

For this case we have the mean and the deviation given:

$\mu = 20.3$

$\sigma = 4.9$

And we can find the limits in order to consider values as significantly low and high like this:

$Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5$

$High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1$

6 0

3 years ago

A single die is rolled. Find the probability of getting an odd number or a number less<br> than 5.

Eddi Din [679]

Answer:

Answer:Rolling a odd number is 1/5 and rolling a number less than five is 3/5

Step-by-step explanation:

3 0

2 years ago

4*5+2*2 answer pls help

45+22 answer pls help