The value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have a system of the equation:
3y=x-2 ..(1)
y=-2x+4 ...(2)
From the equation (2) take the value of y and plug in the equation (1)
3(-2x+4) = x -2
-6x + 12 = x - 2
7x = 14
x = 14/7
x = 2
Plug this value in the equation (2)
y = -2(2) + 4
y = 0
Thus, the value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
Learn more about the linear equation here:
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Ok from the given the best choice to go with will be option B because its going from an up right and its going to flip and rotate.
A = -0.7
B = -9/16 (0.5623)
C = -0.4
D = -5/16 (0.3125)
The last option is correct
Answer:
Read the explanation down
Step-by-step explanation:
This is a linear equation, because the equation does not have any exponents. Graph it by putting the equation into either slope-intercept form y=mx+b or point-slope form y−y1=m(x−x1).
Isolate y by first adding 6x to each side:
9y=6x−18
Divide each side by 9:
y=23x−2
Now graph the line y=23x−2 by first plotting the y intercept at (0,−2), then connecting points with a slope of 23.
graph{2/3x-2 [-10, 10, -5, 5]}
Answer:
Often, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring. While factoring may not always be successful, the Quadratic Formula can always find the solution.
The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.
