3 years ago

The expression (27y^-2)^1/3 / y^-2/3 can be simplified and written without negative exponents as

Mathematics

1 answer:

Phoenix [80]3 years ago

4 0

Answer:

Step-by-step explanation:

$\displaystyle\tt \frac{(27y^{-2})^{\frac{1}{3}}}{y^{-\frac{2}{3}}}=\frac{(3^3\cdot y^{-2})^{\frac{1}{3}}}{y^{-\frac{2}{3}}}=\frac{3\cdot y^{-\frac{2}{3}}}{y^{-\frac{2}{3}}}=3$

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