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ozzi
3 years ago
11

The expression (27y^-2)^1/3 / y^-2/3 can be simplified and written without negative exponents as

Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

3

Step-by-step explanation:

\displaystyle\tt \frac{(27y^{-2})^{\frac{1}{3}}}{y^{-\frac{2}{3}}}=\frac{(3^3\cdot y^{-2})^{\frac{1}{3}}}{y^{-\frac{2}{3}}}=\frac{3\cdot y^{-\frac{2}{3}}}{y^{-\frac{2}{3}}}=3

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Will give brainliest
kodGreya [7K]

Answer: y=12 x =9

Step-by-step explanation:

In a parallelogram the diagonals bisect each other making them equal.

this means 2y + 6 = 30

we can rearrange this as 30 - 6 = 2y

24 = 2y  therefore y = 12

3x - 3 = 24

We can rearrange this as 24 + 3 = 3x

3x = 27

27 / 3 = 9

x = 9

Hope this helped :)

3 0
3 years ago
this dot plot shows the number of cakes sold each day in aunt alice's cake shop last month? what is the median number
elena55 [62]
Where’s the dot plot
4 0
3 years ago
Which is the value of this expression when a=5 and k=-2?<br> [3^2a^-2]^k<br> [3a^-1]
Alex Ar [27]

Answer:243 /3125

(Decimal: 0.07776)

Step-by-step explanation:((32)(5−2))2(3(5−1))

((32)(5−2))2(3(5−1))

3 0
3 years ago
Cards are dealt, one at a time, from a standard 52-card deck. a if the first 2 cards are both spades, what is the probability th
ratelena [41]
So we already drew two cards and both of them are spades. So that means there are 50 cards and 11 spades left.

Then third card being spades would be 11 / 50

Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49

Fifth card would be 9 / 48.

So the probability of next three cards being spades would be
\dfrac{11}{50}\cdot\dfrac{10}{49}\cdot\dfrac9{48}=\dfrac{33}{3920}\approx\boxed{0.00842}

Hope this helps.
3 0
3 years ago
Solve B/3= 18<br> Please help
AnnZ [28]

Answer:

b=54

Step-by-step explanation:

<em>Solve for  </em>b<em>  by simplifying both sides of the equation, then isolating the variable.</em>

Hope this helps :)

<em>-ilovejiminssi♡</em>

3 0
3 years ago
Read 2 more answers
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