Question

The expression (27y^-2)^1/3 / y^-2/3 can be simplified and written without negative exponents as

Answer 1

Answer:

3

Step-by-step explanation:

$\displaystyle\tt \frac{(27y^{-2})^{\frac{1}{3}}}{y^{-\frac{2}{3}}}=\frac{(3^3\cdot y^{-2})^{\frac{1}{3}}}{y^{-\frac{2}{3}}}=\frac{3\cdot y^{-\frac{2}{3}}}{y^{-\frac{2}{3}}}=3$