To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=12 and j+k=b=8, so j and k must be 2 and 6
Then the factors are just (a+j)(a+k), in this case:
(a+2)(a+6)
So the missing term was 6
Answer:
41
Step-by-step explanation:
1.C) -4a-8-a = -5a-8
2. C)-2 - x - 4.3= -6.3 -x
3.A) -2x+6-x-4= -3x+2
hope it helps
If you mean american dollars (which you most likely do) then it would be:
100 = 12285.
1000 = 122850.
10.000 = 1228.10
hope i helped
10 is your common difference
