SOLUTION:
A normal distribution would model this situation because the distribution is approximately symmetrical, thus the mean, median and mode are approximately the same and the population size is large ( greater than 30).
A. have each student vote in first period on monday. the one with the most votes win.
3328 ounces in total
416 bags
401 bags left
Answer:
1. 18 (sqrt21 - sqrt2a)
2. 3
3. x^m/n
4. (5x^4√10)/(√2x)
5. x = -2 or -6
6. x = 30
Step-by-step explanation:
Number 1
3^3sqrt21 - 6^3sqrt2a
3 * 6 * sqrt21 - sqrt2a
18 (sqrt21 - sqrt2a)
Number 2
3^1/2 * 3^1/2 =
3^1/2+1/2 =
3^1 =
3
Number 3
^nsqrtx^m =
x^m/n
Number 4
(√250x^16)/(√2x) =
(√25 * 10 * x^16)/√(2x )=
(5x^4√10)/(√2x)
Number 5
√2x + 13 - 5 = x
√2x + 13 = x + 5
square both side to take away the sqrt sign
(√2x + 13)^2 = (x + 5)^2
expand the equation on the RHS
2x + 13 = x(x+5) + 5(x+5)
2x+13 = x^2 + 10x +25
substract 13 from both sides
2x = x^s + 10x +12
subtract 2x from both sides
0 = x^2 +8x + 12
Factorize equation
x^2 + 6x +2x + 12 = 0
x(x+6) + 2(x+6) = 0
(x+2)(x+6) = 0
x = -2 or -6
Number 6
3 ^5sqrt(x+2)^3 + 3 = 27
subtract 3 from both sides
3 ^5sqrt(x+2)^3 = 27 - 3
3 ^5sqrt(x+2)^3 = 24
divide through by 3
^5sqrt(x+2)^3 = 8
square both sides by 5 to take away the 5th root sign
(x+2)^3 = (8)^5
(x+2)^3 = 32,768
take the cube root of both sides to take away the ^3
x+2 = ^3sqrt 32,768
x+2 = 32
x = 32 - 2
x = 30
Answer: I got -14x-13
But it sounds wrong but I have a picture
Step-by-step explanation:
