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3 years ago

Which expression is equivalent to (5x^3)(4x)^3?

Mathematics

2 answers:

I am Lyosha [343]3 years ago

8 0

Answer:

320 x^6

Step-by-step explanation:

(5x^3)(4x)^3

5 x^3 * 4^3 * x*3

5x^3 *64x^3

320 x^6

shusha [124]3 years ago

3 0

Answer:

Step-by-step explanation:

= 5x^3 * 4^3 * x^3

= 5x^3 *64x^3

= 320x^6

Hope this helps!

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Find Exact Answers, Show your work. BRANLIEST ASAP!! THANK YOU

4vir4ik [10]

$$\cos\theta=\frac{\text{5}}{\text{13}}, \ \sin\theta=\frac{\text{12}}{13}, \ \tan\theta=\frac{\text{12}}{\text{5}}$

$$\sec\theta=\frac{\text{13}}{\text{5}},\ \csc \theta=\frac{\text{13}}{\text{12}} , \ \cot \theta=\frac{\text{5}}{\text{12}}$

Solution:

Given triangle is a right triangle.

Base = 5, Hypotenuse = 13, Height = ?

Height (h) = opposite

<em>In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.</em>

$5^2+h^2=13^2$

$25+h^2=169$

$h^2=144$

Taking square root on both sides.

h = 12

$$\cos\theta=\frac{\text{Base}}{\text{Hypotenuse}}$

$$\cos\theta=\frac{\text{5}}{\text{13}}$

$$\sin\theta=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$$\sin\theta=\frac{\text{12}}{13}$

$$\tan\theta=\frac{\text{Opposite}}{\text{Base}}$

$$\tan\theta=\frac{\text{12}}{\text{5}}$

$$\sec\theta=\frac{\text{Hypotenuse}}{\text{Base }}$

$$\sec\theta=\frac{\text{13}}{\text{5}}$

$$\csc \theta=\frac{\text{Hypotenuse}}{\text{Opposite }}$

$$\csc \theta=\frac{\text{13}}{\text{12}}$

$$\cot \theta=\frac{\text{Base }}{\text{Opposite}}$

$$\cot \theta=\frac{\text{5}}{\text{12}}$

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