Answer:
15/13
Step-by-step explanation:
Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
Please show the rest of the question if there is any
Answer: Second option is correct.
Step-by-step explanation:
Since we have two spinners,
Each spinner has 10 equal sectors labeled with the numbers from 1 to 10.
Primes numbers from 1 to 10 is given by
So, number of outcomes shows a primes number from 1 to 10 = 4
Similarly ,
Composite numbers from 1 to 10 is given by
So, number of outcomes shows a composite number from 1 to 10 =5
∴ Total outcomes show a prime number on the first spinner and a composite number on the second spinner is given by
Thus, Second option is correct.
