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3 years ago

What are th minimum,first quartile,median,third quartile,and maximum of the data set? 12,6,8,3,10,15,18,7

Mathematics

2 answers:

Arturiano [62]3 years ago

5 0

Minimum: 3
First Q: 6
Median: 9
Third Q:15
Maximum: 18

masya89 [10]3 years ago

3 0

You have to put it in order first so it would be:
3,6,7,8,10,12,15,18
Minimum: 3
Quartile 1: 6.5
Quartile 2: 9
Quartile 3: 13.5
Maximum: 18

After that, you make a Box Plot and put it on there. I was doing this in class today. :)

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Point A, located at (-11,17) on the coordinate plane, is reflected over the x-axis to form point B. Then point B is reflected ov

zalisa [80]

Answer:

B = (-11, -17)

C = (11, -17)

Step-by-step explanation:

Reflection over the x-axis is accomplished by changing the sign of the y-coordinate:

(x, y) ⇒ (x, -y) . . . . . reflection over x-axis

Reflection over the y-axis is accomplished by changing the sign of the x-coordinate:

(x, y) ⇒ (-x, y) . . . . . reflection over the y-axis

B = (-11, -17)

C = (11, -17)

Check

Reflection over both axes negates both coordinates. It is equivalent to reflection over the origin, or rotation 180°.

A(-11, 17) ⇒ C(11, -17) . . . . . both coordinates change sign

3 0

3 years ago

S varies inversely as G. If S is 8 when G is 1.5, find S when G is 3. a) Write the variation. b) Find S when G is 3.

ss7ja [257]

Step-by-step explanation:

$s \: = \frac{k}{g}$

$8 = \frac{k}{1.5}$

$k \: = 1.5 \times 8 = 12$

$s = \frac{12}{g}$

$s = \frac{12}{3}$

s = 4

4 0

3 years ago

Convert 40g into degrees

Lera25 [3.4K]

Answer:

40g= 36 in degrees (decimal), and 36 degrees 0' 0" in degrees (Minutes&Seconds)

Step-by-step explanation:

8 0

3 years ago

Determine if the lim f(x) exists using the graph below.. If it does, find its value. If it does not,x 1explain why

Leno4ka [110]

The limit of a function f at a point a exists if:

$\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)$ $\begin{gathered} \text{ From the given image, the value of the left limit of f at x=1 } \\ \lim_{x\to a^-}f(x)\lt1 \end{gathered}$

Also,

$\begin{gathered} \text{ From the given image, the value of the right limit of f at x=1 } \\ \lim_{x\to a^+}f(x)\gt1 \end{gathered}$

Therefore,

$\lim_{x\to1^-}f(x)\lim_{x\to1^+}f(x)$

Hence, the limit does not exist

8 0

1 year ago

Please someone help me with this

Ivenika [448]

Answer:

See explanation

Step-by-step explanation:

Triangle ABC ahs vertices at points A(-4,-4), B(-1,-2) and C(-1,-4).

1 way: First reflect this triangle across the y-axis to form the triangle A''B''C'' which vertices are at points A''(4,-4), B''(1,-2) and C''(1,-4).

Then translate this triangle 7 units up to form the triangle A'B'C' with vertices:

$A'(4,-4+7)=A'(4,3)\\ \\B'(1,-2+7)=B'(1,5)\\ \\C'(1,-4+7)=C'(1,3)$

2 way: First translate this triangle 7 units up to form the triangle A''B''C'' which vertices are at points A''(-4,3), B''(-1,5) and C''(-1,3).

Then reflect this triangle across the y-axis to form the triangle A'B'C' with vertices:

$A'(-(-4),3)=A'(4,3)\\ \\B'(-(-1),5)=B'(1,5)\\ \\C'(-(-1),3)=C'(1,3)$

8 0

3 years ago