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PilotLPTM [1.2K]
3 years ago
7

What are th minimum,first quartile,median,third quartile,and maximum of the data set? 12,6,8,3,10,15,18,7

Mathematics
2 answers:
Arturiano [62]3 years ago
5 0
Minimum: 3
First Q: 6
Median: 9
Third Q:15
Maximum: 18
masya89 [10]3 years ago
3 0
You have to put it in order first so it would be:
3,6,7,8,10,12,15,18
Minimum: 3
Quartile 1: 6.5
Quartile 2: 9
Quartile 3: 13.5
Maximum: 18

After that, you make a Box Plot and put it on there. I was doing this in class today. :)
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The​ half-life of radium is 1690 years. If 20 grams are present​ now, how much will be present in 250 ​years?
Aneli [31]

Answer:

  18.05 g

Step-by-step explanation:

The multiplier of the initial quantity is ...

  (1/2)^(t/1690)

so, for t=250, this becomes ...

  (1/2)^(250/1690) ≈ 0.902545

Then the quantity remaining of the initial 20 g is ...

  (20 g)(0.902545) ≈ 18.05 g

3 0
3 years ago
I really need help for this geometry question, I would appreciate any help thank you.
Vsevolod [243]
You know that you have the Opposite side and the Adjacent side. therefore you would use Tangent (T= O/A)
because you are finding the angle you would go Tan^-1(12÷20) =31°
it is 12÷20 because O/A and the 12 is the opposite side therefore It would be O and 20 is the adjacent side therefore equaling 20 so O/A = 12/20
Your answer is 31°
8 0
2 years ago
A number k is greater than 3. Which of the following is true about 승 ? 1 It is between 3 3 It is equal to 1 It is greater than 1
Alekssandra [29.7K]

If the number k is greater than 3, we have the following inequality:

k>3

In order to evaluate k/3, let's divide the inequality by 3:

\begin{gathered} k>3 \\ \frac{k}{3}>\frac{3}{3} \\ \frac{k}{3}>1 \end{gathered}

So the expression k/3 is greater than 1, therefore the correct option is D.

3 0
1 year ago
A die is tossed. If the number rolled is between 2 and 5, inclusive, what is the probability the number rolled is 4?
lesya [120]
<h2>The possibility is Likely.</h2>
5 0
3 years ago
Suppose 10000 people are given a medical test for a disease. About1% of all people have this condition. The test results have a
Alina [70]

Answer:

The percent of the people who tested positive actually have the disease is 38.64%.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person has the disease

<em>P</em> = the test result is positive

<em>N</em> = the test result is negative

Given:

P(X)=0.01\\P(P|X^{c})=0.15\\P(N|X)=0.10

Compute the value of P (P|X) as follows:

P(P|X)=1-P(P|X^{c})=1-0.15=0.85

Compute the probability of a positive test result as follows:

P(P)=P(P|X)P(X)+P(P|X^{c})P(X^{c})\\=(0.85\times0.10)+(0.15\times0.90)\\=0.22

Compute the probability of a person having the disease given that he/she was tested positive as follows:

P(X|P)=\frac{P(P|X)P(X)}{P(P)}=\frac{0.85\times0.10}{0.22} =0.3864

The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.

3 0
3 years ago
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