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mezya [45]
3 years ago
8

Solve for x. Explain each step you took to solve this question. 30 (9x-3)

Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0
I believe the answer would be X=7
It’s been a little bit
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What is it mean? <br> a. 27.19 <br> b. 27.29 <br> c. 28.10 <br> d. 28.11
Len [333]
Mean is average so you sum up all 4 numbers and divide by 4. Answer is 27.6725 or rounded 27.67

Have a nice day. Hope this helps.
3 0
2 years ago
Help me plz I don’t understand
puteri [66]
Emma’s statement makes sense and Charles’ doesn’t, bcuz when you say 0.75 it should be 75 tenths, because it’s less than a whole number, but charles said 7 and 5 tenths, if it’s 7 and 5 tenths, it would be 7.5.
3 0
3 years ago
A typical cell phone plan has a fixed base fee that’s includes a certain amounts of over a charge
Romashka [77]

The answer is 2)C=30+62(g-2)

6 0
3 years ago
1. Consider the following hypotheses:
Andrej [43]

Answer:

See deductions below

Step-by-step explanation:

1)

a) p(y)∧q(y) for some y (Existencial instantiation to H1)

b) q(y) for some y (Simplification of a))

c) q(y) → r(y) for all y (Universal instatiation to H2)

d) r(y) for some y (Modus Ponens using b and c)

e) p(y) for some y (Simplification of a)

f) p(y)∧r(y) for some y (Conjunction of d) and e))

g) ∃x (p(x) ∧ r(x)) (Existencial generalization of f)

2)

a) ¬C(x) → ¬A(x) for all x (Universal instatiation of H1)

b) A(x) for some x (Existencial instatiation of H3)

c) ¬(¬C(x)) for some x (Modus Tollens using a and b)

d) C(x) for some x (Double negation of c)

e) A(x) → ∀y B(y) for all x (Universal instantiation of H2)

f)  ∀y B(y) (Modus ponens using b and e)

g) B(y) for all y (Universal instantiation of f)

h) B(x)∧C(x) for some x (Conjunction of g and d, selecting y=x on g)

i) ∃x (B(x) ∧ C(x)) (Existencial generalization of h)

3) We will prove that this formula leads to a contradiction.

a) ∀y (P (x, y) ↔ ¬P (y, y)) for some x (Existencial instatiation of hypothesis)

b) P (x, y) ↔ ¬P (y, y) for some x, and for all y (Universal instantiation of a)

c) P (x, x) ↔ ¬P (x, x) (Take y=x in b)

But c) is a contradiction (for example, using truth tables). Hence the formula is not satisfiable.

7 0
3 years ago
What is the value of x in the equation 2(x – 3) + 9 = 3(x + 1) + x?
Lana71 [14]

Answer:

Given the equation: 2(x-3)+9=3(x+1)+x

Distributive property of multiplication states that when a number is multiplied by the sum of the two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately i.e,

a \cdot (b+c) = a\cdot b+a\cdot c

Now, using distributive property to LHS and RHS, we get

2x-6+9=3x+3+x

Combine like terms on RHS;

2x-6+9 = 4x+3

or

2x+3 = 4x+3

Subtract 3 from both sides of an equation;

2x+3-3 =4x+3-3

Simplify:

2x = 4x

or

4x-2x =0

2x = 0

⇒ x =0

Therefore, the value of x in the given equation

2(x-3)+9=3(x+1)+x is 0.




8 0
3 years ago
Read 2 more answers
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