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3 years ago

Compare 0.56 and 0.65

Mathematics

2 answers:

abruzzese [7]3 years ago

7 0

0.56 < 0.65
or 0.56 is less than 0.65

Veronika [31]3 years ago

5 0

0.56 is less than 0.65

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Alex and glen share a 30 ounce bucket of clay by the end of the week alex has used 1/10 of the bucket and glen has used 2/5 of t

Mamont248 [21]

Answer:

21 ounces

Step-by-step explanation:

6 0

3 years ago

Given the functions f(x) = 2x -1 and g(x) =

Novosadov [1.4K]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

f(x) = 2x - 1

g(x) = 2 - x

f(x) + g(x) = (2x - 1) + (2 - x)

= 2x -1 + 2 - x

= x + 1

f(x) - g(x) = (2x - 1) - (2 - x)

= 2x - 1 - 2 + x

= 3x - 3

g(-5) - f(-5)

Putting x = -5 in g(x) = 2 - x

g(x) = 2 - x

g(-5) = 2 - (-5) = 2+5 = 7

Putting x = -5 in f(x) = 2x - 1

f(x) = 2x - 1

f(-5) = 2(-5) - 1

= -10 - 1

= -11

Thus,

g(-5) - f(-5) = 7 - (-11) = 7+11 = 18

f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2

f(g(x)) = f(2-x)

= 2(2-x)-1

= 4-2x-1

= 3-2x

6 0

3 years ago

3. Six neighborhood children - Leisha, Benito, Delia, Charlotte, Weldon, and Zina- were measured

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Zina, weldon, delia, leisha, bento, charlotte

8 0

3 years ago

Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data

tresset_1 [31]

Based on the information represented by the boxplot ;

Latasha's lowest sale amount = 50

Kayla's median is between 200 and 300

Latasha has a greater spread due to higher IQR value

1.) The Lowest amount of sale made by Latasha in one month

The minimum value is denoted by the starting position of the lower whisker on a boxplot.

Lowest amount of sale made by Latasha = 50

2.) 50% of sales made by Kayla :

50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

50% of sales made by Kayla is between 200 and 300

With median sale value being 250

3.) Spread of the middle 50% of sales :

The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

IQR = Upper Quartile (Q3) - Lower quartile(Q1)

For Latasha :

Q3 = 450 (Endpoint of the box)
Q1 = 150 (starting point of the box)

IQR = 450 - 150 = 300

For Kayla :

Q3 = 375 (Endpoint of the box)
Q1 = 100 (starting point of the box)
IQR = 375 - 100 = 275

Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

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2 years ago

Which statement about the equation is true?

Papessa [141]

The equation has no solution

8 0

4 years ago

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