Your question is difficult to understand, that is why I am going to edit your question as follow:
<u>Edited Question:</u>
Cone A and B both have a volume of 48π Cubic units but have different dimensions. Cone A has a radius=6 units and a height=4 units.
Find the one possible radius and height for cone B be to have the same volume as cone A.
Answer:
Radius of cone B= 6units
Height of cone B=units
Step-by-step explanation:
As we know the formula for the volume of a cone is
![V=\pi\ r^{2}\frac{h}{3}](https://tex.z-dn.net/?f=V%3D%5Cpi%5C%20r%5E%7B2%7D%5Cfrac%7Bh%7D%7B3%7D)
If volume of A and Volume B is given as same, thus
![V_{A}=V_{B}](https://tex.z-dn.net/?f=V_%7BA%7D%3DV_%7BB%7D)
![\pi\ (R_{A}) ^{2}\frac{H_{A} }{3} =\pi\ (R_{B}) ^{2}\frac{H_{B} }{3}](https://tex.z-dn.net/?f=%5Cpi%5C%20%28R_%7BA%7D%29%20%5E%7B2%7D%5Cfrac%7BH_%7BA%7D%20%7D%7B3%7D%20%20%3D%5Cpi%5C%20%28R_%7BB%7D%29%20%5E%7B2%7D%5Cfrac%7BH_%7BB%7D%20%7D%7B3%7D)
comparing equations above, we get
![R_{A}=R_{B}\\H_{A}=H_{B}](https://tex.z-dn.net/?f=R_%7BA%7D%3DR_%7BB%7D%5C%5CH_%7BA%7D%3DH_%7BB%7D)
Thus, Radius of cone A=6units
and
Height of cone B= 4units
Answer:
Step-by-step explanation:
- Dilation of 0.5 from ABCD to A'B'C'D'
- Rotation of 90° counterclockwise
Answer: 2sin^2x+sin2x+cos2x=0 ..... (1).
By using the trigonometric identities below :
sin2x=2sinxcosx
cos2x=cos^2x-sin^2x
We substitute the trigonometric identities into (1).
2sin^2x+2sinxcosx+cos^2x-sin^2x=0
By combining like terms .
sin^2x+2sinxcosx+cos^2x=0.....(2)
The equation (2) is equivalent to the following expression (3).
(sinx+cosx)(sinx+cosx)=0 .....(3).
sinx+cosx=0
cosx=-sinx
divide both sides by cosx
1=-sinx/cosx
-1=sinx/cosx
sinx/cosx=tanx
substitute
-1=tanx
tanx=-1
tangent is negative in 2nd and 4th quadrants
tan135º=-1 (one answer)
tan315º=-1 (second answer)
Step-by-step explanation:
Please refer to the trigonometric identities used and explained above .
Step-by-step explanation:
the right answer is A option