Answer:
Yes,there is a significant association shell weight and the widths of the opercula
Step-by-step explanation:
Using a correlation Coefficient calculator :
Given the data above :
The Coefficient of correlation(r) obtained is :
0.7632
Obtaining the test statistic :
T = r² / √(1 - r²) / (n - 2)
T = 0.7632² / √(1 - 0.7632²) / (10 - 2)
T = 0.58247424 / 0.2284528
Test statistic = 2.550
The Pvalue from r score , N = 10
Pvalue(0.7632, 10) = 0.01022
α = 0.05
If Pvalue < α ; reject H0
Pvalue < α ; We conclude that there is a significant association shell weights and the widths of the opercula
It's actually: I = PRT
I = Interest
P = Principle
R = Rate
T = Time
Step-by-step explanation:
go left 10 and down 2 this due to the numbers being negative.
Answer:
x = 24/13
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
18/13 = 3/4x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Divide both sides by 3/4: x = 24/13
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: 18/13 = 3/4(24/13)
- Multiply: 18/13 = 18/13