1/3; 39%; 2/5; 0.42
hope this helps!
Answer:

Step-by-step explanation:
Let
P----> the initial price of the ticket
y ---> the price of the ticket after t years
t---> the time in years
we know that
100%+8%=108%=108/100=1.08
so
----> equation A
If the price is doubled
then
-----> equation B
equate equation A and equation B and solve for t

Simplify

Apply log both sides


Taking Rhs
1/2 [sin(x+y)+ sin (x-y)]
using sinA + sin B = 2 cos (A+B)/2 cos( A - B)/2
1/2 [ 2 Cos ( x+y+x-y)/2 . Cos (x+y-x+y)/2]
=Cos 2x/2. Cos 2y/2 = Cos x . Cos y
Hence true
Answer:
no solution
Step-by-step explanation:
Simplifying
11q + -6 = 3q + 8q
Reorder the terms:
-6 + 11q = 3q + 8q
Combine like terms: 3q + 8q = 11q
-6 + 11q = 11q
Add '-11q' to each side of the equation.
-6 + 11q + -11q = 11q + -11q
Combine like terms: 11q + -11q = 0
-6 + 0 = 11q + -11q
-6 = 11q + -11q
Combine like terms: 11q + -11q = 0
-6 = 0
Solving
-6 = 0
Couldn't find a variable to solve for.
This equation is invalid, the left and right sides are not equal, therefore there is no solution.