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Anon25 [30]
3 years ago
7

I need help please.....

Mathematics
1 answer:
fgiga [73]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Move the decimal to the right 4 times

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I ran 800m, 5km,1,000cm. How many meters did I run all together
Ugo [173]

Answer:

5810 meters

Step-by-step explanation:

800 meters

5km = 5,000 meters

1,000 cm = 10 meters

Add all together to get 5810 meters

8 0
3 years ago
What is the constant of proportionality between y and x in the graph?
FinnZ [79.3K]

Answer:

4

Step-by-step explanation:

Constant of proportionality refers to the slope of the line in this case, the slope of the line is (4-0)/(1-0)=4

3 0
3 years ago
The length of a quarter is 0.955 inch. Round the length of a quarter to the nearest tenth of an inch
uysha [10]

Answer:

the answer to the question is 0.96.

5 0
3 years ago
Read 2 more answers
A bag contains three red marbles, three green ones, one lavender one, one How many sets of five marbles include at least two red
dimaraw [331]

Answer with Step-by-step explanation:

The number of marbles are as under

3 red , 3 green , 1 Lavender total = 7

Now to select five marbles from a total of 7 marbles such that at least 2 marbles are included are the sum of the following cases:

1) We select 2 exactly 2 red marbles from 3 reds and the remaining 3 marbles are selected from 4 of other colours

Thus n_{1}=\binom{3}{2}\binom{4}{3}=\frac{3!}{2!}\cdot \frac{4!}{3!}=12

2)We select all the 3 red marbles and the remaining 2 are selected from the remaining 4 marbles

n_2=\binom{4}{2}=\frac{4!}{2!\cdot 2!}=6

Thus the total number of ways are n_1+n_2=12+6=18

3 0
3 years ago
Solve the system of equation by guess sidle method
lilavasa [31]

Answer: The solution is,

x_1\approx 0.876

x_2\approx 0.419

x_3\approx 0.574

Step-by-step explanation:

Given equations are,

8x_1 + x_2 + x_3 = 8

2x_1 + 4x_2 + x_3 = 4

x_1 + 3x_2 + 5x_3 = 5,

From the above equations,

x_1=\frac{1}{8}(8-x_2-x_3)

x_2=\frac{1}{4}(4-2x_1-x_3)

x_3=\frac{1}{5}(5-x_1-3x_2)

First approximation,

x_1(1)=\frac{1}{8}(8-(0)-(0))=1

x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5

x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5

Second approximation,

x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875

x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375

x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625

Third approximation,

x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875

x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875

x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875

Fourth approximation,

x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781

x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141

x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359

Fifth approximation,

x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938

x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691

x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598

Hence, by the Gauss Seidel method the solution of the given system is,

x_1\approx 0.876

x_2\approx 0.419

x_3\approx 0.574

4 0
3 years ago
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