Ask question

Ask question

All categories

3 years ago

7

I need help please.....

1 answer:

fgiga [73]3 years ago

7 0

Answer:

C

Step-by-step explanation:

Move the decimal to the right 4 times

You might be interested in

I ran 800m, 5km,1,000cm. How many meters did I run all together

Ugo [173]

Answer:

5810 meters

Step-by-step explanation:

800 meters

5km = 5,000 meters

1,000 cm = 10 meters

Add all together to get 5810 meters

8 0

3 years ago

What is the constant of proportionality between y and x in the graph?

FinnZ [79.3K]

Answer:

4

Step-by-step explanation:

Constant of proportionality refers to the slope of the line in this case, the slope of the line is (4-0)/(1-0)=4

3 0

3 years ago

The length of a quarter is 0.955 inch. Round the length of a quarter to the nearest tenth of an inch

uysha [10]

Answer:

the answer to the question is 0.96.

5 0

3 years ago

Read 2 more answers

A bag contains three red marbles, three green ones, one lavender one, one How many sets of five marbles include at least two red

dimaraw [331]

Answer with Step-by-step explanation:

The number of marbles are as under

3 red , 3 green , 1 Lavender total = 7

Now to select five marbles from a total of 7 marbles such that at least 2 marbles are included are the sum of the following cases:

1) We select 2 exactly 2 red marbles from 3 reds and the remaining 3 marbles are selected from 4 of other colours

Thus $n_{1}=\binom{3}{2}\binom{4}{3}=\frac{3!}{2!}\cdot \frac{4!}{3!}=12$

2)We select all the 3 red marbles and the remaining 2 are selected from the remaining 4 marbles

$n_2=\binom{4}{2}=\frac{4!}{2!\cdot 2!}=6$

Thus the total number of ways are $n_1+n_2=12+6=18$

3 0

3 years ago

Solve the system of equation by guess sidle method

lilavasa [31]

Answer: The solution is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

Step-by-step explanation:

Given equations are,

$8x_1 + x_2 + x_3 = 8$

$2x_1 + 4x_2 + x_3 = 4$

$x_1 + 3x_2 + 5x_3 = 5$ ,

From the above equations,

$x_1=\frac{1}{8}(8-x_2-x_3)$

$x_2=\frac{1}{4}(4-2x_1-x_3)$

$x_3=\frac{1}{5}(5-x_1-3x_2)$

First approximation,

$x_1(1)=\frac{1}{8}(8-(0)-(0))=1$

$x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5$

$x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5$

Second approximation,

$x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875$

$x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375$

$x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625$

Third approximation,

$x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875$

$x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875$

$x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875$

Fourth approximation,

$x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781$

$x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141$

$x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359$

Fifth approximation,

$x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938$

$x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691$

$x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598$

Hence, by the Gauss Seidel method the solution of the given system is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

4 0

3 years ago