Let r be the lesser root and r^2 be the greater.......the sum of the roots = -b/a = -[-6] / 1 = 6
So we have that
r^2 + r = 6 → r^2 + r - 6 = 0
Factor
(r + 3) (r - 2) = 0
So r = -3 or r = 2
Then r^2 = 9 or r^2 =4
And the product of the roots = c/a = k/a = k
So....k = (-3)(9) = -27 or k = (2)(4) = 8
Check
x^2 - 6x - 27 = 0 factors as (x + 3)(x - 9) = 0 and the roots are -3 and 9
x^2 - 6x + 8 = 0 factors as (x -2) (x - 4) =0 and the roots are 2 and 4
Y=mx+b
m=slope
perpendicular lines have slopes that multiply to get -1
the slopes are
for
and
, the slope are
since their product is -1, the lines are perpendicular
ednocrkdlwmqcw e9rbeuopgjkmr qoejffwkf ,rwfrwfjr nmwrfHELP ME iuehf[eoiffkjkmfeiufkwjmfwufuStep-by-step explanation:
I would say B.
Your starting term is 10, so that is your a1 value. Each time you add 4 to the number before, like 10+4=14 and so on, so that would mean (a-1)+4.
Answer:
3 3/4 - 3 1/12 = 2/3
Step-by-step explanation:
You are finding the difference which means subtraction.
