22/3 sorry I accidentally deleted steps
Answer: cos²(θ) + sin(θ)sin(e)
<u>Step-by-step explanation:</u>
sin (90° - θ)cos(Ф) - sin(180° + θ) sin(e)
Note the following identities:
sin (90° - θ) = cos(x)
sin (180° + θ) = -sin(x)
Substitute those identities into the expression:
cos(x)cos(x) - -sin(x)sin(e)
= cos²(x) + sin(x)sin(e)
Answer:
![\left[\begin{array}{ccc}9\\10\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%5C%5C10%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Multiply the components of A by 3 then add corresponding components of
3a + b
3![\left[\begin{array}{ccc}2\\4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}3\\-2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}6\\12\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C12%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+
= ![\left[\begin{array}{ccc}6+3\\12-2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%2B3%5C%5C12-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
Its B.6 because when you plug in 1 for y the equation is 3x-1=17 and you have to cancel out y to get 3x=18 by itself because you have to add 1 to the 17 since you canceled it out of the equation then you are left with 3x=18 and you divide both sides by 3 and then 18 divided by 3 is 6 so x=6
