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sdas [7]
4 years ago
12

What is the value of the expression when a = 5, b = 4 , and c = 6?⁢ 4a2b−c

Mathematics
2 answers:
Alex787 [66]4 years ago
8 0

Answer:

10

Step-by-step explanation: i clicked 5 on my quiz and got 60% the correct answer is 10

Julli [10]4 years ago
4 0
I hope this helps you




4.5^2.4-6



16.25-6


400-6


394
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Pls help me with this one -4 divided by - 2/3
Karolina [17]

Answer:

6

Step-by-step explanation:

-\frac{4}{1} * -\frac{3}{2}  = \frac{12}{2}  = 6

5 0
3 years ago
Three-fourths of the tickets had been sold, and there were 420 tickets left. How many tickets were printed?
Reil [10]

Answer:

Step-by-step explanation:

420 = 1/4 so 4/4 is 4 420s

420 x 4 = 1680

8 0
3 years ago
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A Game Center has a $5 admission fee and charges $0.50 for each game played. Write an equation that represents the cost, C, in d
Dvinal [7]
Answer: $0.50c+$5=n Jensen
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3 years ago
Travelling at 60km a car completes a journey in 3 1/4 hours calcualate the distance travelled<br>​
LuckyWell [14K]

Answer:

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4 0
3 years ago
Two socks are selected at random from a draw of loose socks- there are 4 green socks and 6 yellow socks
lara [203]

Using the hypergeometric distribution, it is found that there is a 0.1333 = 13.33% probability that two of the socks will both be green if the socks are drawn without replacement.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem, we have that the values of the parameters are:

N = 10, k = 4, n = 2.

The probability that both are green is P(X = 2), hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,10,2,4) = \frac{C_{4,2}C_{6,0}}{C_{10,2}} = 0.1333

0.1333 = 13.33% probability that two of the socks will both be green if the socks are drawn without replacement.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

#SPJ1

4 0
2 years ago
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