This is a geometric sequence with first term 2 and common ratio 5.
an = a1 r^(n-1) IS THE GENERAL FORM SO HERE IT IS:-
an = 2(5)^(n-1)
Answer: Binomial
Step-by-step explanation:
1 / 3
A binomial setting has a set number of trials, and the variable in question is the number of
successes that occur in those trials.
A geometric setting does not have a set number of trials, and the variable in question is the
number of trials it takes to get the first success.
In both settings, the trials are independent and the probability of success remains the same on
each trial.
2/3
In this game, the player rolls 7 dice, and F is the number of dice that show a 5. So the variable is
counting the number of successes
The rolls are independent, and the probability of getting a 5 is the same on each roll,
3/3
F is a binomial variable
Answer:
Step-by-step explanation:
(7,6) (-3,-1)
(x1,y1) (x2,y2)
![Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\=\sqrt{(-3-7)^{2}+(-1-6)^{2}}\\\\=\sqrt{(-10)^{2}+(-7)^{2}}\\\\=\sqrt{100+49}=\sqrt{149}\\\\=12.21](https://tex.z-dn.net/?f=Distance%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%28-3-7%29%5E%7B2%7D%2B%28-1-6%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%28-10%29%5E%7B2%7D%2B%28-7%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B100%2B49%7D%3D%5Csqrt%7B149%7D%5C%5C%5C%5C%3D12.21)
2.25h(60m/hr)(1/3)=45m
So Rick spends 45 minutes studying math per night.
Answer:
y= -x+7, b= sqrt(2P/a), c=3P^2-b
Step-by-step explanation:
First, make a table regarding both of the equations. You will eventually find out that both lines intersect at the point (2, 5) after you find the points on the table. From there, subtract x from both sides in the equation x + y = 2. You will get y = -x + 2. Since they said the line was parallel, find a line that has the slope of negative one. Since we know that this line intersects the point in which the first two lines intersect, we know that the y-intercept will be 7. The equation of the line would be y=-x+7.
Multiply both sides by 2. Then, divide both sides by a to get b^2=(2P/a). Take the square root to get the value of b, which is sqrt(2P/a).
Square both sides of the equation to get P^2=(b+c)/3. Cross multiply to get 3P^2=b+c. Subtract b from both sides to get c=3P^2-b.