Answer:Assuming all three, we shall find that each of the relations in 3:14 leads to a ... Then by 3:15 the relations AD//BC and AB||DE imply AD//CE, which excludes ... From 2:72, 3:11, 3:14, and 3:16 we deduce 3:19 If A, B, C are three distinct ... a point D lies between X and Y in AB/C if it belongs to XY/C, that is, if XY||CD
Step-by-step explanation:
7.) By clusterring $7.04 + $5.95 + $6.08 + $5.06 + $6.12 = $6.00 + $6.00 + $6.00 + $6.00 + $6.00 = $30.00
8.) 9.3 + 8.7 + 8.91 + 9.052 = 9 + 9 + 9 + 9 = 36
9.) 37.6 + 44.1 + 41 + 39.1 = 40 + 40 + 40 + 40 = 160
In clustering method you look for a whole number usually ending with 0 which all the given numbers "clustered" around.
Answer:
-1 and - 6
Step-by-step explanation:
Since you cannot have the denominator 0..... - 1 and - 6
make the denominator 0. Therefore they are excluded values
Answer: 11,830
Step-by-step explanation: