Answer:
og angle: 126.8
complementary angle: 53.2
og angle mirror (if any): 126.8
complementary angle mirror (if any): 53.2
Domain of

are the values of x for which 2x + 1 < 0
2x < -1
x < -1/2
Therefore, domain is all real numbers less than -1/2
Answer:
Option C (4096π in²)
Step-by-step explanation:
Area of the circle = 256π in²
We know that
, where r = radius of the circle
So,

Cancelling π from both the sides,


The radius of the circle = 16 in.
When the radius is multiplied with 4 , new radius = 16×4 = 64 in.
New Area = 
Try comparing your solution with the following:
Solution:

Answer:

Check:
![2[10-13(\frac{40}{17})]+9(\frac{40}{17})=-34(\frac{40}{17})+60\\-20=-20](https://tex.z-dn.net/?f=2%5B10-13%28%5Cfrac%7B40%7D%7B17%7D%29%5D%2B9%28%5Cfrac%7B40%7D%7B17%7D%29%3D-34%28%5Cfrac%7B40%7D%7B17%7D%29%2B60%5C%5C-20%3D-20)
<em>Hope this was helpful.</em>
Answer:
Rock D.
Step-by-step explanation:
We can assume that the force that the catapult does is always the same.
So, here we need to remember Newton's second law:
F = m*a
force equals mass times acceleration.
Where acceleration is the rate of change of the velocity.
So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.
So, we can rewrite:
a = F/m
So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.
Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.
So we can assume that rock D is the correct option.