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Wittaler [7]
3 years ago
13

Find x please help this is literally my final exam

Mathematics
1 answer:
hoa [83]3 years ago
8 0

Answer is B

Step-by-step explanation:

You have the side opposite the angle and the Hypotenuse so use soh

Sine(x) = opposite/Hypotenuse

Sine(x) = 9/19

X = sin-1(9/19) - - - - - here the - 1 is to the power of

X= 28,27371363

X= 23,3

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Hello, this is what I’ve got so far, please help me somebody!
topjm [15]

Answer:

6 .... 1

3 ... 1/100

9.... 1/1000

7 0
3 years ago
You are inviting 30 friends to a party. You know that each person eats, on average,
nika2105 [10]

Answer:

11.25 pizzas

Step-by-step explanation:

We are given that:

There are 30 friends total

Each eat 3 slices

1 pizza has 8 slices

So, with the given information, you can know that

Number of slices pizza that all 30 friends eat = 30*3 = 90 slices

Each pizza have 8 slices so we need 90 slices so we need in total of:

Number of pizzas need = 90/8 = 11.25 pizzas

Hope this help you :3

8 0
3 years ago
Solve 30x -12,000 less than or equal to 980
Lyrx [107]

Answer:

\large\boxed{x\leq432\dfrac{2}{3}\to x\in\left(-\infty,\ 432\dfrac{2}{3}\right]}

Step-by-step explanation:

30x-12,000\leq980\qquad\text{add 12,000 to both sides}\\\\30x-12,000+12,000\leq980+12,000\\\\30x\leq12,980\qquad\text{divide both sides by 30}\\\\x\leq\dfrac{12,980}{30}\\\\x\leq\dfrac{1,298}{3}\\\\x\leq432\dfrac{2}{3}

6 0
3 years ago
What is the advantage of using exponential notification
MAVERICK [17]
<span>I found the following about exponential notation at this site: http://www.vendian.org/envelope/dir0/exponential_notation.html "Exponential notation lets you move the decimal point in a number. It simplifies numbers by getting rid of zeros, and making math easier. Getting rid of zeros helps with big 100,000,000 and small 0.000,000,001 numbers.
</span><span>hope this helped

</span>
3 0
3 years ago
What is the product of (3p-7)(2p²-3p-4)
garik1379 [7]

Answer:

Choice C is the correct answer.

Step-by-step explanation:

Given expression is

(3p-7)(2p²-3p-4)

we have to find the product of linear expression to quardatic expression.

Firstly, multiply 3p to quardatic expression and -7 to quardatic expression and add.

3p(2p²-3p-4)-7(2p²-3p-4)

Multiply 3p to each term of quardatic expression and -7 to each term of quardatic expression and add all terms:

3p(2p²)+3p(-3p)+3p(-4)-7(2p²)-7(-3p)-7(-4)

6p³-9p²-12p-14p²+21p+28

add like terms

6p³+(-9-14)p²+p(-12+21)+28

6p³-23p²+9p+28 which is the correct answer.


3 0
3 years ago
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