Supposing a normal distribution, we find that:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
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We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>
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In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- The Z-score measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u>
</u>
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In this problem:
- Mean of 8.8 inches, thus
. - Standard deviation of 2.8 inches, thus
.
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The interquartile range(IQR) is the difference between the 75th and the 25th percentile.
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25th percentile:
- X when Z has a p-value of 0.25, so X when Z = -0.675.




75th percentile:
- X when Z has a p-value of 0.75, so X when Z = 0.675.




The IQR is:

What is the diameter, in inches, of the smallest tree that is an outlier?
- The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

The diameter of the smallest tree that is an outlier is of 16.36 inches.
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A similar problem is given at brainly.com/question/15683591
Answer: None of the above
Step-by-step explanation:
Given


Now, integrating both sides



A.15 b.500 c.40 d.7.5 yeah, not to confident but I think it's correct.
Answer:
big bet XD
Step-by-step explanation:
Hello! I can help you with this!
4.
a. $100
b. $360
The formula to find the answers to these kinds of problems is p * r * t. The rate is always a decimal, so if the rate is 8%, you multiply by 0.08. If the rate is 12%, you multiply by 0.12, and so on.
5.
a. 12.8
b. 31 1/6
I got these answers by doing the distributive property. Replace each variable with the number it represents, multiply each by two and add them up to get these answers. For the fraction one, you can set up each fraction by finding the LCD before multiplying by 2, or you can find a fraction calculator online and add the numbers up.
6.
a. x = 20
b. x = 3
c. x = 13
d. x = 0
e. x = 4
f. x = 7
g. x = -3
I solved this problem by doing the distributive property and doing these kinds of problems step by step. It’s long to explain, but hopefully your teacher has good notes for you to look back on over these types of questions. If there is only a negative sign in front of the distributive property equation, then you basically distribute -1 to each number. In these long equations, combine like terms. You must do these kinds of questions right, because it’s easy to mess up and get wrong answers if you don’t do the right steps in order.