Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
the answer is 5 dimes and 1 nickel.
hope this helps <3
Area of a parallelogram = bh
First, find b (base):
b = 12
Then find h (height):
h = 10
Multiply:
120
The answer is D) 120 units^2
Answer:
x ≈ 7.4
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos22° = =
Multiply both sides by 8
8 × cos22° = x, thus
x ≈ 7.4 ( to the nearest tenth )