The number of miles in a day at which the rental costs for Company A and Company B are the same is 140 miles
<h3>Rental cost</h3>
Let
Company A:
90 + 0.20x
Company B:
20 + 0.70x
90 + 0.20x = 20 + 0.70x
90 - 20 = 0.70x - 0.20x
70 = 0.50x
- Divide both sides by 0.50
x = 70/0.50
x = 140 miles
Therefore, the number of miles in a day at which the rental costs for Company A and Company B are the same is 140 miles
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Answer:
Its 3
Step-by-step explanation:
Sub (x+1) for x
f(x+1)=2(x+1)^2+3
f(x+1)=2(x^2+2x+1)+3
f(x+1)=2x^2+4x+2+3
f(x+1)=2x^2+4x+5
D is answer
Answer:
<u>It</u><u> </u><u>moved</u><u> </u><u>for</u><u> </u><u>1</u><u>5</u><u>2</u><u>.</u><u>7</u><u> </u><u>seconds</u>
Step-by-step explanation:
Time taken/ period, T :

substitute the variables:

In seconds:

Y + 79 + 37 = 180
y + 116 = 180
y = 64