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Shtirlitz [24]
3 years ago
5

Annual sales for a fast food restaurant are 650000 and are increasing at a rate of 4% per year. Use an exponential function to f

ind the annual sales after 7 years.
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
5 0

The value after 7 years is $ 855355.65

<em><u>Solution:</u></em>

Given that, Annual sales for a fast food restaurant are 650000 and are increasing at a rate of 4% per year

To find:  exponential function to find the annual sales after 7 years

<em><u>The exponential growth function is given as:</u></em>

y = a(1+r)^t

Where,

"a" is the initial amount

"y" is the future value

"r" is the rate of interest in decimal

"t" is the number of years

Here in this given question,

a = 650000

t = 7 years

r = 4 \% = \frac{4}{100} = 0.04

<em><u>Substituting the values in given formula,</u></em>

y = 650000(1+0.04)^7\\\\y = 650000(1.04)^7\\\\y = 650000 \times 1.31593\\\\y = 855355.65

Thus the value after 7 years is $ 855355.65

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Marissa has a wool rug that has the shape of a regular octagon in her living room. The diameter of the incircle of the rug measu
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We know that the diameter of the inner circle (d) and the side of a regular octagon (s) are tied by the formula:

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How can you check to see if two ratios form a proportion? Explain the method you used to find the answer to the previous problem
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In problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. To find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

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In problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. To find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

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(3/5)^2+4X3-2 what is the value of the expression
Sliva [168]

Answer:

10.36

Step-by-step explanation:

So your solution would be:

(\frac{3}{5})^{2} + 4 \times 3 - 2

=(\frac{3}{5})^{2} + 4 \times 3 - 2

=\dfrac{3^{2}}{5^{2}} + 4 \times 3 - 2

=\dfrac{9}{25} + 4 \times 3 - 2

=0.36 + 4 \times 3 - 2

=0.36 + 12 - 2

=12.36 - 2

=10.36

Just try to remember PEMDAS.

Parenthesis, Exponent, Multiplication/Division, Addition/Subtraction.

This is the order we follow when going about expressions with many operations.

Let's start with the parenthesis part. Notice that there is an exponent beside the parenthesis enclosing the fraction. Here we use the quotient to a power rule. We distribute the exponent to the numerator and the denominator.

=(\frac{3}{5})^{2} + 4 \times 3 - 2\\

=\dfrac{3^{2}}{5^{2}} + 4 \times 3 - 2

=\dfrac{9}{25} + 4 \times 3 - 2

Now that we got the parenthesis and exponent out of the way, let's move on to the next. Multiplication/Division. Whichever comes first, you do it first.

We have a fraction so we do that first. Then we do the multiplication after.

=0.36 + 4 \times 3 - 2

=0.36 + 12 - 2

Next we do the addition/subtraction. Again, whichever comes first.

=12.36 - 2

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7 0
3 years ago
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

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Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

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So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

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There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
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