He buys three cups of hot choclate cause 1.50*3= 4.50
and he buys 5 cups of coffe cause 2.25*5=11.25
and 11.25 + 4.50=15.75
Answer:

Step-by-step explanation:
Ok, so we start by setting the integral up. The integral we need to solve is:

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:
U=5+x
du=dx
x=U-5
so when substituting the integral will look like this:

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

so we must define p, q, p' and q':
p=ln U


q'=U-5
and now we plug these into the formula:

Which simplifies to:

Which solves to:

so we can substitute U back, so we get:

and now we can simplify:



notice how all the constants were combined into one big constant C.
If you have 1/5 and 2/3, you need a common denominator to even do anything. So three and five both go into 15, so then you do 2 times 5, cause 3 times 5 is 15. And 1 times 3, cause 3 times 5 is 15. So you end up with 3/15 as produce, and 10/15 as vegetables. So, then you divide the fractions, 1/5 divided by 10/15, which is the same as 1/5 times 15/10. So your answer is 3/10 of the produce is vegetables.
31 rotations, hope i was a big help to you
Answer:
x = 4
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below
P.s: I used the Law of Sines, but there are many other ways to solve it