OK first convert one of the equations into Y=MX+b form
Y-2x = 3
Add 2X
Y = 2x +3
Now substitute this equation in the other one.
So it would be
3X - 2Y = 5
3X-2(2x+3) = 5
Now solve for y
3X - 4X - 6 = 5
-1X - 6 = 5
Add 6
-1X = 11
X = -11
Now substitute this into one of the equations
Y - 2X = 3
Y -2(-11) = 3
Y +22 = 3
y = 3-22
y = -19
Collins’ new shoes were 3 times the amount of his lunch. You’re welcome!
Split up the interval [0, 3] into 3 equally spaced subintervals of length 
. So we have the partition
[0, 1] U [1, 2] U [2, 3]
The left endpoint of the 
-th subinterval is
where 
.
Then the area is given by the definite integral and approximated by the left-hand Riemann sum
A square has 4 right angels and 4 sides with equal angels ;)
