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Rama09 [41]
4 years ago
5

Simplify: 2{10-5+x[1+3(6-2)]}

Mathematics
1 answer:
REY [17]4 years ago
3 0

Answer:

10+26x

Step-by-step explanation:

To solve this, work your way from the inner most parentheses to the outer most:

  1. The inner most parentheses is around 6-2, meaning you solve this first. When you solve this, you get 4.
  2. The second most inner parentheses is around (1+3 times 4) using PEMDAS, you first solve the multiplication, and then add. Once you solve this, you get 13.
  3. Next, the outer most parentheses is around (10-5+13x). When you simplify this, you get 5+13x
  4. Finally, you multiply 2(5+13x). Using distributive property, you get 10+26x as your final simplified answer.
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the length of a rectangle is 4 inches greater than the width. the perimeter of the rectangle is 24in what are the dimensions of
Murljashka [212]
Let's say:
lengh=x
width=y

"The length of a rectangle is 4 inches greater than the width."
That means: x=y+4 (in inches).

the parameter is (by definition) 2*lenght+2*width.

so we have 2*x+2y=24.
we also know that x=y+4

Substituting:

2*(y+4)+2y=24.
2*y+8+2y=24
4*y+8=24//substitute 8 from both sides
4*y=16//dividing both sides by 4.

y=4
So the width is 4!

The lenght is y+4=8!
the dimensions are 4 by 8.
(check: 2*4+2*8=24, correct!)
5 0
4 years ago
How Would you solve 4 ≤ -5 -x Please include your steps
Serga [27]

4 ≤ -5 - x

x ≤ -5 - 4

x ≤ -9

x ∈ (-∞; -9]

5 0
4 years ago
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Two numbers have a difference of 24. What is the sum of their squares if it is a minimum?
seraphim [82]
Let "a" and "b" be some number where:

a - b = 24

We want to find where a^2 + b^2 is a minimum.  Instead of just logically figuring out that the answer is where a=b=12, I'll just use derivatives.

So we can first substitute for "a" where a = b+24

So we have (b+24)^2 + b^2 = b^2 +48b +576 + b^2
And that equals 2b^2 +48b +576

Then we take the derivative and set it equal to zero:

4b +48 = 0
4(b+12) = 0
b + 12 = 0
b = -12

Thus "a" must equal 12.

So:
a = 12
b = -12

And the sum of those two numbers squared is (12)^2 + (-12)^2 = 144 + 144 = 288.

The smallest sum is 288.
3 0
3 years ago
Indicate a general rule for the nth term of the sequence when a1 = 5 and r = √3 .
Dmitriy789 [7]

the right answer is an=5(3)^(n-1)/2

3 0
3 years ago
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The function f(x) = 200 × (1.098)x represents a village's population while it is growing at the rate of 9.8% per year.
AlexFokin [52]

The time for the village to dig the new well is about 7 1/2 years. At this time the population doubles from its current size.

<h3>How to graph a function?</h3>

For a function f(x) = y, the steps to draw a graph for the given function are as follows:

  • Consider certain values of x
  • Substitute x values in the given function to obtain y values
  • Plot the x and y values in the graph
  • Join the points to know the variation.

<h3>Calculation:</h3>

It is given that,

f(x) = 200 × (1.098)^x

Village's population growing rate = 9.8%

Creating a table for x and f(x) values:

x: 0   2   4   6   8   10

f(x = 0) = f(0) = 200 × (1.098)^0 = 200

f(x = 2) = f(2) = 200 × (1.098)^2 = 241

f(x = 4) = f(4) = 200 × (1.098)^4 = 291

f(x = 6) = f(6) = 200 × (1.098)^6 = 350

f(x = 8) = f(8) = 200 × (1.098)^8 = 423

f(x = 10) = f(10) = 200 × (1.098)^1^0 = 509

So,

(x, f(x)): (0, 200)  (2, 241)  (4, 291)  (6, 350)  (8, 423)  (10, 509)

Plotting these points in the graph and joining the points, the graph is shown below.

Finding the time for the village to dig a new well:

It is given that the population doubled from its current size, the village will need to dig new water well.

The current size of the village = 200

If it doubles for a certain time 't' = 400

So,

400 = 200 × (1.098)^t

⇒ (1.098)^t = 2

⇒ log(1.098)^t = log 2

⇒ t log(1.098) = 0.301

⇒ t × 0.04 = 0.301

∴ t = 7.525 years

Therefore, the village's population becomes double at the time 7 and half years from now. So, after 7 1/2 years, the village needs to dig a new well.

Learn more about the function and its graph here:

brainly.com/question/4025726

#SPJ1

3 0
2 years ago
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