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2 years ago

Divide Whole Numbers - Tutorial - Level D ) What is 859 - 3?

Mathematics

1 answer:

patriot [66]2 years ago

6 0

Answer:

the answer is 856

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Find the surface area of the<br> rectangular prism.<br> 3 cm<br> 10 cm<br> 7 cm<br> [?] sq cm

Setler79 [48]

Answer:

Step-by-step explanation:

There are six faces on the prism:

Two faces are 7 cm by 10 cm, area = 7×10 = 70 cm² each

Two faces are 7 cm by 3 cm, area = 7×3 = 21 cm² each

Two faces are 10 cm by 3 cm, area = 10×3 = 30 cm² each

surface area = 2(70) + 2(21) + 2(30) = 140 + 42 + 60 = 242 cm²

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2 years ago

Proof Pythagorean identities:

dimulka [17.4K]

<h2>Sorry, But I don't know!!</h2>

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2 years ago

What is the exact value of tan 30° ? enter your answer, as a simplified fraction, in the box?

attashe74 [19]

In this question , we have to find the value of tan 30 and we need to write the answer in simplified form .

$tan x = \frac{sin x}{ cos x}$

Substituting the values of sin (30) and cos(30, we will get

$tan (30) = \frac{1/2}{ \sqrt{3} /2}$

Multiplying both numerator and denominator by 2, we will get

$tan(30 ) = \frac{1}{ \sqrt3}$

TO simplify it, we need to multiply both numerator and denominator by square root 3.

$tan(30) = \frac{ \sqrt 3}{ \sqrt3 * \sqrt 3} = \frac{ \sqrt 3}{3}$

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2 years ago

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In a jar of 250 jelly beans, a random sample of 25 is pulled. In the random sample, 15 of the jelly beans are red. How many jell

vovangra [49]

150 jelly beans are most likely to be red
You can multiply both numbers by ten

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1 year ago

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Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

stealth61 [152]

Answer:

Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Thus, Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

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2 years ago

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