Divide Whole Numbers - Tutorial - Level D ) What is 859

If you can, answer at least 2 question I put 10 points on it

igomit [66]

Answer:

a) one solution(x = 9)

b) no solution

c) infinite solutions

Step-by-step explanation:

a) To solve this equation, we can add 4 on both sides in order to isolate x:

x - 4 =5

+ 4 + 4

x = 9

Since x equals 9, that counts as only one solution, as there is only one value of x that makes the equation true.

b) We start by subtracting 2x from both sides to combine the variable terms:

2x - 6 = 2x + 5

-2x -2x

-6 = 5

The statement, -6 = 5 is never true and it is not dependent on the value of x. This means there are no solutions to this equation.

c) We can start by subtracting 3x from both sides to combine the terms with x:

3x + 12 = 3x + 12

-3x -3x

12 = 12

The statement above is always true, and no matter the value of x, it will always be true. This means there are infinite solutions to the equation.

8 0

2 years ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

4x-(12 divided 3) +2x=20

Savatey [412]

Answer:

4

Step-by-step explanation:

3 0

3 years ago

If a basketball is bounced at a angle of 30 degrees, it will bounce off the court at and angle of

Serjik [45]

Answer:

I think it's 30

Step-by-step explanation:

I took it as reflection of light..or ig it has same idea

6 0

2 years ago

Help me with this: How many residents were surveyed?

PtichkaEL [24]

22 you just count all of the dots

7 0

2 years ago

Divide Whole Numbers - Tutorial - Level D ) What is 859 - 3?