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3 years ago

Please help!!

1 answer:

8 0

Let the width = w.
The length is 6 times the width, so the length is 6w.
The perimeter is 70.
P = 2L + 2W

70 = 2(6w) + 2(w)

70 = 12w + 4w

70 = 14w

5 = w

The width is 5.
The length is 6 times the width, so the length is 6 * 5 = 30

Area of rectangle = LW

A = 5 * 30 = 150

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Solve the following inequality: ALGEBRA 1

zimovet [89]

Answer:

-10

Step-by-step explanation:

4 0

2 years ago

Find the volume of each cylinders. Round your answers to the nearest tenth if necessary. Use 3.14 for T.

wariber [46]

V= πr^2xh

π=3.14
r=6ft
h=8ft

V=3.14x6^2x8=3.14x36x8=904.32ft^3

3 0

3 years ago

Water is being pumped into a conical tank that is 8 feet tall and has a diameter of 10 feet. If the water is being pumped in at

Deffense [45]

The rate of change of the depth of water in the tank when the tank is half

filled can be found using chain rule of differentiation.

When the tank is half filled, the depth of the water is changing at 1.213 ×

10⁻² ft.³/hour.

Reasons:

The given parameter are;

Height of the conical tank, h = 8 feet

Diameter of the conical tank, d = 10 feet

Rate at which water is being pumped into the tank, = 3/5 ft.³/hr.

Required:

The rate at which the depth of the water in the tank is changing when the

tank is half full.

Solution:

The radius of the tank, r = d ÷ 2

∴ r = 10 ft. ÷ 2 = 5 ft.

Using similar triangles, we have;

$\dfrac{r}{h} = \dfrac{5}{8}$

The volume of the tank is therefore;

$V = \mathbf{\dfrac{1}{3} \cdot \pi \cdot r^2 \cdot h}$

$r = \dfrac{5}{8} \times h$

Therefore;

$V = \dfrac{1}{3} \cdot \pi \cdot \left( \dfrac{5}{8} \times h\right)^2 \cdot h = \dfrac{25 \cdot h^3 \cdot \pi}{192}$

By chain rule of differentiation, we have;

$\dfrac{dV}{dt} = \mathbf{\dfrac{dV}{dh} \cdot \dfrac{dh}{dt}}$

$\dfrac{dV}{dh}=\dfrac{d}{h} \left( \dfrac{25 \cdot h^3 \cdot \pi}{192} \right) = \mathbf{\dfrac{25 \cdot h^2 \cdot \pi}{64}}$

$\dfrac{dV}{dt} = \dfrac{3}{5} \ ft.^3/hour$

Which gives;

$\dfrac{3}{5} = \mathbf{\dfrac{25 \cdot h^2 \cdot \pi}{64} \times \dfrac{dh}{dt}}$

When the tank is half filled, we have;

$V_{1/2} = \dfrac{1}{2} \times \dfrac{1}{3} \times \pi \times 5^2 \times 8 =\mathbf{ \dfrac{25 \cdot h^3 \cdot \pi}{ 192}}$

Solving gives;

h³ = 256

h = ∛256

$\dfrac{3}{5} \times \dfrac{64}{25 \cdot h^2 \cdot \pi} = \dfrac{dh}{dt}$

Which gives;

$\dfrac{dh}{dt} = \dfrac{3}{5} \times \dfrac{64}{25 \cdot (\sqrt[3]{256}) ^2 \cdot \pi} \approx \mathbf{1.213\times 10^{-2}}$

When the tank is half filled, the depth of the water is changing at 1.213 × 10⁻² ft.³/hour.

Learn more here:

brainly.com/question/9168560

6 0

3 years ago

5/6 - 1/3 Answers should be in the format 5/2 or 2/5. No decimals or mixed numbers.

uysha [10]

Answer:

Answer is 1/2

I clearly didn't understand the question u said it should be 5/2 or 2/5 or in fractional form

8 0

4 years ago

Garrett is 64 inches how many centimeters tall is he round your answer to the nearest tenth of a centimeter. 1 in.=2.54cm

Marysya12 [62]

To answer this we just need to convert by multiplying. Lets do it:-

1 in = 2.54 cm

64 × 2.54 = 162.56
64 in = 162.56 cm.

To round 162.56 to the nearest tenth we will look at 162.56. Since this number is 5 we will round to the next number which will make it 162.60.

So, 64 in = 162.56 cm rounded to the nearest tenth is 162.60.

Hope I helped ya!!

7 0

3 years ago

Read 2 more answers