Answer:
<u> BC = 10 and AD = 30</u>
Step-by-step explanation:
In figure-1 , AB = CD ,BK ⊥ AD, AK = 10, KD = 20.
Since, line AD is sum of AK and KD, then
AD = AK + KD
AD = 10 + 20
AD = 30
Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD
so, BC = KL and AK = LD
KL = AD - LD
KL = 20 - 10
KL = 10
Since, BC = KL then BC = 10
Hence, <u> BC = 10 and AD = 30</u>
First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have
Which means that the roots are
Next, we can expand the function definition:
In this form, it is much easier to compute the derivative:
If we evaluate the derivative in the points of interest, we have
This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation
is what we need. The three lines are:
This is the tangent at x = -2
This is the tangent at x = 0
This is the tangent at x = 1