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3 years ago

13

A totem pole that is 90 feet tall casts a shadow that is 45 feet long. At the same time, a 6 – foot tall man casts a shadow that

is x feet long. Find the length of the shadow.

1 answer:

12345 [234]3 years ago

8 0

Answer:

x=90+45/6

x=135/6

x=22.5

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The conference table top shown is the shape of two congruent trapezoids. The table top is wooden with a rectangular glass inset.

Papessa [141]

I think it’s 196? base 1 +base 2=28 radius is 7 but we need the whole thing so 7x2=14.
then multiply and then divide by 2 28X14= 392 divided by 2 = 196

7 0

2 years ago

Solve this equation -k/5=7/10

liberstina [14]

$-\dfrac{k}{5}=\dfrac{7}{10}\\
-10k=35\\
k=-3.5$

4 0

2 years ago

PLEASEEEEE HELPPPPP!!!!

Dmitry_Shevchenko [17]

Step One

Find AM

Formula

AM = MN - AN

Givens

MN = 67.2

AN = 32

Solution

AM - 67,2 - 32

AM = 35.2

Step Two

Set up a solution

67.2/35.2 = 81.9/x Cross Muliply

67.2 * x = 81.9 * 35.2 Combine the right

67.2 * x = 2882.88 Divide by 67.2

x = 2882.88/67.2

x = 42.9 Answer

3 0

2 years ago

Pls help me solve this question, also include step by step calculation ya. Thks

sp2606 [1]

$\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}$

Step-by-step explanation:

$5x^2-x^2e^{2x}+2e^{2x}=10$

$Let:\ x^2=t \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}$

<em>Prologarithmize both parts of the equation:</em>

$ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\$

<u><em> Divide both parts of the equation by 2:</em></u>

$\displaystyle\\x=\frac{ln5}{2}$

$t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}$

6 0

1 year ago

What is ∛1728. Then multiplied by ∛14903

NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate $\sqrt[3]{1728}$ and then multiply the result by $\sqrt[3]{14903}$

Let us first evaluate $\sqrt[3]{1728}$

$\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12$

As need to multiply 12 by $\sqrt[3]{14903}$

$\Rightarrow 12 \times \sqrt[3]{14903}$

On solving $\sqrt[3]{14903}$ , we get

$\sqrt[3]{14903}=24.608$

$\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306$

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

8 0

2 years ago