I am pretty sure your asking for a conversion of 10,300milliliters to cm3 and L.
If so then this should be the answer 10,300cm3 and 10.3L. Hope this helps.
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Answer: Electronegativity difference of F and Cl: 1.0 and is covalent
Explanation:
2KClO₃ ---> 2KCl + 3O₂
2 mol 2 mol 3 mol
When 2 mol of KClO₃ decompose, 3 mol of oxygen are produced.
Answer:
A. 7.2%
B. 8.6 ppm
Explanation:
<em>Part A</em>
First let's <em>calculate the mass of I₂</em>, using the known value of moles and the molecular weight (253.8 g/mol)
- 4.0x10⁻² mol I₂ * 253.8 g/mol = 10.152 g I₂
Mass percentage is calculated using the mass of I₂ and the total mass (mass of I₂ + mass of CCl₄)
- Total mass = 130 + 10.152 = 140.152 g
- Mass percentage I₂ = 10.152 / 140.152 * 100 = 7.2%
<em>Part B</em>
The concentration of Sr⁺² in ppm is calculated using the formula
We're given the mass of Sr⁺² in grams, so now we <u>convert it into mg</u>:
- 8.2x10⁻³g * = 8.2 mg
Now to convert kg of water into L, we use the density of seawater (1050 kg/m³):
<em>Converting density</em>: 1050 * = 1.05 kg/L
- Volume of one kilogram of water = 1kgWater ÷ 1.05 kg/L = 0.95 L
Finally we<u> calculate the concentration of Sr⁺²</u>:
- 8.2 mg / 0.95 L = 8.6 ppm
A single water molecule can form 4 Hydrogen Bonds.
A hydrogen atom that is linked to a highly electronegative atom and another highly electronegative atom that is close by interact with one another to form hydrogen bonds, which are an unique kind of attractive intermolecular interactions. This process is known as hydrogen bonding. Hydrogen, for instance, is covalently linked to the more electronegative oxygen atom in water molecules (H2O). Therefore, the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another H2O molecule are what cause hydrogen bonding to form in water molecules.
To learn more about Hydrogen Bonding visit: brainly.com/question/10904296
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