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Neporo4naja [7]
3 years ago
12

Which of the following series of isoelectronic ions (Mg²⁺, N³⁻, F⁻, Si⁴⁺) has the ionic radii in order of largest to smallest? A

) Mg²⁺ > N³⁻ > F⁻ > Si⁴⁺ B) Mg²⁺ > Si⁴⁺ > F⁻ > N³⁻ C) N³⁻ > F⁻ > Si⁴⁺ > Mg²⁺ D) N³⁻ > F⁻ > Mg²⁺ > Si⁴⁺ E) F⁻ > N³⁻ > Si⁴⁺ > Mg²⁺
Chemistry
1 answer:
Rom4ik [11]3 years ago
4 0

Answer:

Option (d) is correct

N³⁻ > F⁻ > Mg²⁺ > Si⁴⁺

Explanation:

Total electrons for all the species = 10

So these are <u>iso electronic</u> with each other.

We know

Ionic radii ∝ \frac{Magnitude of Negative Charge}{Magnitude of Positive Charge}

  • Si⁴⁺ has 14 protons and 10 electrons
  • Mg²⁺ has 12 protons and 10 electrons
  • N³⁻ has 7 protons and 10 electrons
  • F⁻ has 9 protons and 10 electrons
  • Iso electronic species with greatest number of protons have small size and vice versa.
  • So Si⁺⁴ have smallest size and N³⁻ have largest in size
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