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3 years ago

Which type of force is the magnet using to move the nail?

Chemistry

1 answer:

geniusboy [140]3 years ago

7 0

Answer: Nail moving towards a magnet

Explanation: Since the iron nails and pins move towards the magnet, it means that the magnet exerts a force on them. The force exerted by a magnet is called magnetic force.

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Using the following equation for the combustion of octane, calculate the heat associated with the combustion of 100.0 g of octan

Sonja [21]

Answer: B) -4819 kJ

Explanation:

The balanced reaction for combustion of octane is:

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$ $\Delta H^0_{rxn}=-11018kJ$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

given mass of octane = 100.0 g

Molar mass of octane = 114.33 g/mol

Putting in the values we get:

$\text{Number of moles}=\frac{100.0g}{114.33g/mol}=0.8747moles$

According to stoichiometry:

2 moles of octane give heat = -11018 kJ

Thus 0.8747 moles of octane give = $\frac{-11018}{2}\times 0.8747=-4819kJ$

Thus -4819 kJ of heat is released by 100.0 g of octane assuming complete combustion.

5 0

4 years ago

Read 2 more answers

How do you remove unine odor from bedding?

arsen [322]

You could try a chemical from the store that is made to take away odors, or you could try and use fabric softener to make it smell better:)

3 0

4 years ago

A 8.249 gram sample of copper is heated in the presence of excess fluorine. A metal fluoride is formed with a mass of 13.18 g. D

levacccp [35]

Answer:

$CuF_2$ the empirical formula of the metal fluoride.

Explanation:

Mass of copper heated = 8.249 g

Mass of copper fluoride formed = 13.18 g

Mass of fluorine gas in copper fluoride = x

$13.18 g = 8.249 g + x\\x= 13.18 - 8.249 g = 4.931 g$

Moles of copper :

$= \frac{8.249 g}{63.546 g/mol}=0.1298 mol$

Moles of fluorine:

$= \frac{4.931 g}{18.998 g/mol}=0.2596 mol$

For the empirical formula divide the smallest mole of an element with all the moles of elements present in the compound.

$Copper= \frac{0.1298 mol}{0.1298 mol}=1\\Fluorine = \frac{0.2596 mol}{0.1298 mol}=2$

The empirical formula of the copper fluoride = $CuF_2$

$CuF_2$ the empirical formula of the metal fluoride.

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3 years ago

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miss Akunina [59]

Answer:

I can´t see, it isnt clear

Explanation:

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3 years ago

Is the potential energy of the roller coaster elastic or gravitational?

boyakko [2]

Answer:

gravitational

Explanation:

Hope this helps :)

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3 years ago

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