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PSYCHO15rus [73]
3 years ago
6

Using the following image, if JL=120, what are x, JK, and KL.

Mathematics
1 answer:
Vladimir79 [104]3 years ago
7 0
Here for the points :)
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Help me plz i want help plz
netineya [11]

Answer:

384

Step-by-step explanation:

6 squares of 8x8=

8x8x6=384

8 0
3 years ago
Read 2 more answers
Which multiplication expression is eqeul to 3/5 ÷ 1/2
eduard

Answer:

Lets solve = 3/5 ÷ 1/2

3/5 ÷ 1/2

= 3/5 × 2/1

= 3 × 2/5 × 1

= 6/5

In mixed fraction its

1 \frac{1}{5}

____________________

Now lets solve "a" option

3/5 × 2

= 3 × 2/5 × 1

= 6/5

In mixed fraction

1 \frac{1}{5}

So option a = 3/5 x 2/1 is ur answer

8 0
2 years ago
Read 2 more answers
CAN SOMEONE HELP ME PLEASE ASAP!?
Viefleur [7K]

Answer:

axc is 90 degrees. hope that helps

6 0
2 years ago
The position, x, of an object is given by the equation x = A + Bt +Ct2, where t refers to time. What are the dimensions of A, B,
Serjik [45]

Answer: Dimensions of A are of length [L]

Dimensions of B are of LT^{-1}

Dimensions of C are of LT^{-2}

Step-by-step explanation:

The given equation is

x(t)=A+Bt+Ct^{2}

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid

Thus

Dimensions of A = [L]

Dimensions of Bt = [L]

Bt=[L]\\\\[B][T]=[L]\\\\\therefore [B]=LT^{-1}

Similarly

Dimensions of Ct^{}2 = [L]

Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}

4 0
3 years ago
Find the area of the shaded region
Dimas [21]

The area of the shaded region is 15.453 square units.

Step-by-step explanation:

Step 1:

The given shape consists of a rectangle and two circles.

The length of the rectangle is given as 12 cm. Both the diameters of the circles equal 12 cm. So each circle has a diameter of 6 cm and thus a radius of 3 cm.

The diameter of the circle is equal to the width of the rectangle.

So the rectangle has a length of 12 cm and a width of 6 cm. The circles have radii of 3 cm each.

Step 2:

The area of the rectangle = (l)(w) = (12)(6) = 72 square cm.

The area of each circle = \pi r^{2}  = (3.1415)(3^{2} ) = 28.2735 square cm.

The area of both circles =2(28.2735) = 56.547 square cm.

The area of the shaded region is the difference between the area of the rectangle and the area of both circles.

The area of the shaded region = 72 - 56.547 = 15.453 square units.

The area of the shaded region is 15.453 square units.

6 0
2 years ago
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