Simplify 8 over negative 3 divided by negative 4 over 9 . (5 points) -8 -6 6 8
1 answer:
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The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>What is the area of the quadrilateral?</h3>
Herein we have a description of an <em>irregular</em> quadrilateral, whose area must be determined by adding the areas of minor quadrilaterals and triangles that are part of it. The area is now determined:
A = 0.5 · (24 cm) · (7 cm) + 0.5 · (15 cm) · (20 cm)
A = 234 cm²
The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>Remark</h3>
The picture with the quadrilateral is missing and is included as attachment.
To learn more on quadrilaterals: brainly.com/question/13805601
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