Round 8,751 to the nearest hundred.

Mathematics

2 answers:

Kazeer [188]3 years ago

5 0

8 is rounding up so it is 8800

mafiozo [28]3 years ago

4 0

8800 because the last two digits are above 50.

You might be interested in

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

2 years ago

What is the shape 1 circular base and 1curved surface

swat32

Circular based pyramid I believe

6 0

2 years ago

Read 2 more answers

1.4t - 0.4 (t- 3.1) =5.8

GenaCL600 [577]

1 Expand
1.4t-0.4t+1.24=5.8

2 Simplify 1.4t-0.4t+1.241.4t−0.4t+1.24 to t+1.24t+1.24
t+1.24=5.8

3 Subtract 1.241.24 from both sides
t=5.8−1.24

4 Simplify 5.8-1.245.8−1.24 to 4.564.56
t=4.56

7 0

3 years ago

Look at each equation and possible solution. Is the solution correct? Select Yes or No for each equation.

oksano4ka [1.4K]

Answer:

yes

Step-by-step explanation:

7 0

2 years ago

How do i factor the expressions 4w-16?

igomit [66]

The answer to this would be 4(w-4)

7 0

3 years ago