What is the best estimate for the quotient 5,397 divided by 62
2 answers:
Answer:
The best estimate is 90.
Step-by-step explanation:
Given : Quotient 5,397 divided by 62 .
To find : The best estimate of the given situation.
Solution : We solve this by approximating the term and then divide to get solution.
Approximation is rounding off the number
→ When the ones digit is greater than 5 (5, 6, 7, 8, or 9) then it round the number up.
→ When the ones digit is less than 5 ( 0, 1, 2, 3, or 4) then it round the number down.
Approximation of 5397 to hundredth is 5400
Approximation of 62 to tenth is 60
Now, divide 5400 by 60
Therefore, The best estimate is 90.
We can also cross check by actual division of 5397 by 62.
When we approximate 87.04 it round off to 90.
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Answer:
Step-by-step explanation:
y > 3x + 10
y < -3x - 1
<h3> Part A:</h3>You'd graph the given systems of linear inequalities the same way as you graph the linear equations.
To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph. Use a dashed line (because of the ">" symbol).
Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).
Pick a test point on either side of the boundary line and plug it into the original problem. This will help determine which side of the boundary line is the solution. Plug in a test point that is not on the boundary line.
Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.
y > 3x + 10
0 > 3(0) + 10
0 > 0 + 10
0 > 10 (False statement).
y < -3x - 1
0 < -3(0) - 1
0 < 0 - 1
0 < -1 (false statement).
Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.
<h3>Part B: </h3>
You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.
y > 3x + 10
10 > 3(8) + 10
10 > 24 + 10
10 > 34 (False statement).
y < -3x - 1
10 < -3(8) - 1
10 < -24 - 1
10 < -25 (false statement).
Therefore, (8, 10) is not a solution to the system.
