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Mumz [18]
3 years ago
10

a patio is shaped like a trapezoid. it has the base of 25 feet and the height of 14 feet. Mary is going to stain the patio with

a stain that costs $12.00 a gallon. One gallon will cover 200 square feet. the stain she has chosen can only be purchased in gallon containers. how many gallons of stain does Mary need to buy to stain the patio and how much in total will she pay for the stain? ❗️please help❗️
Mathematics
2 answers:
erik [133]3 years ago
7 0
The minimum height of the patio is <span>#"14 ft."#</span>
ivann1987 [24]3 years ago
7 0
Hey there bro!

To start this all out, (what \ formula \ will \ we \ even \ use?)

We are going to use to following:

\left[\begin{array}{ccc}\boxed{\boxed{A= \frac{a+b}{2}h}} \end{array}\right]

We would then, 

\Longrightarrow \ (add \ base \ and \ the \ size \ of \ the \ based) \\ \\&#10;&#10;\Longrightarrow \ (then \ we \ divide \ by (2) \ then \ multiply \ it \ by (h)) \\ \\

By doing this, our sum of these would give us . . . .

\left[\begin{array}{ccc}(350\end{array}\right]

SO, IF THE PAINT ONLY COVERS (200) SQUARE FEET, AND 350 WOULD ALMOST BE THE DOUBLE OF 200, WE WOULD THEN UNDERSTAND MORE ON HOW TO FIND SHE WOULD NED TO BUY FOR THE PATIO.


We would then do \left[\begin{array}{ccc}(12/4)\end{array}\right] because this is (350) and then from here, we would know how much more she would need.

So, if she only uses ($12.00) for 200 square feet, then we do.

($12.00) + ($4.00) = \boxed{\boxed{16.00}} dollars.

She would only need to spend ($16.00) bucks.

Hope this helps you bro! :)
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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

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The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

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