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Mumz [18]
3 years ago
10

a patio is shaped like a trapezoid. it has the base of 25 feet and the height of 14 feet. Mary is going to stain the patio with

a stain that costs $12.00 a gallon. One gallon will cover 200 square feet. the stain she has chosen can only be purchased in gallon containers. how many gallons of stain does Mary need to buy to stain the patio and how much in total will she pay for the stain? ❗️please help❗️
Mathematics
2 answers:
erik [133]3 years ago
7 0
The minimum height of the patio is <span>#"14 ft."#</span>
ivann1987 [24]3 years ago
7 0
Hey there bro!

To start this all out, (what \ formula \ will \ we \ even \ use?)

We are going to use to following:

\left[\begin{array}{ccc}\boxed{\boxed{A= \frac{a+b}{2}h}} \end{array}\right]

We would then, 

\Longrightarrow \ (add \ base \ and \ the \ size \ of \ the \ based) \\ \\&#10;&#10;\Longrightarrow \ (then \ we \ divide \ by (2) \ then \ multiply \ it \ by (h)) \\ \\

By doing this, our sum of these would give us . . . .

\left[\begin{array}{ccc}(350\end{array}\right]

SO, IF THE PAINT ONLY COVERS (200) SQUARE FEET, AND 350 WOULD ALMOST BE THE DOUBLE OF 200, WE WOULD THEN UNDERSTAND MORE ON HOW TO FIND SHE WOULD NED TO BUY FOR THE PATIO.


We would then do \left[\begin{array}{ccc}(12/4)\end{array}\right] because this is (350) and then from here, we would know how much more she would need.

So, if she only uses ($12.00) for 200 square feet, then we do.

($12.00) + ($4.00) = \boxed{\boxed{16.00}} dollars.

She would only need to spend ($16.00) bucks.

Hope this helps you bro! :)
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Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

5 0
4 years ago
What is 18,307 in expanded form?
olga_2 [115]

Answer:

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Step-by-step explanation:

18,307

= 10000 + 8000 + 300 + 7

4 0
3 years ago
One serving of yogurt has 95 calories.
fiasKO [112]

Answer:

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The drawing will help

7 0
3 years ago
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
4 years ago
Help me out please. Correct answers only
Sergio [31]

Answer:

c=39

Step-by-step explanation:

4+2=6

To remove square root you have to square everything making the 6 a 36 and then add 3. At the end it is a 39.

8 0
3 years ago
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