Question

Which theorem or postulate proves that △ABC and △DEF are similar?

Answer 1

Answer: SAS

Step-by-step explanation:

SAS so it would be C

Answer 2

Answer:

△ABC and △DEF are similar by SAS Similarity Theorem.

Option (C) is correct .

Step-by-step explanation:

Definition of SAS Similarity property

Two triangles are said to be similar by SAS Similarity property If two sides are proportional and one corresponding angle congruent .

In △ABC and △DEF

$\frac{ED}{AB}= \frac{7}{21}$

$\frac{ED}{AB}= \frac{1}{3}$

and

$\frac{EF}{BC}= \frac{11}{33}$

$\frac{EF}{BC}= \frac{1}{3}$

Thus

$\frac{ED}{AB}=\frac{EF}{BC}= \frac{1}{3}$

∠ABC = ∠DEF  (As given in the figure )

Thus △ABC and △DEF are similar by SAS Similarity property .