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Vaselesa [24]
3 years ago
12

Which theorem or postulate proves that △ABC and △DEF are similar?

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
8 0

Answer: SAS

Step-by-step explanation:

SAS so it would be C

yan [13]3 years ago
7 0

Answer:

△ABC and △DEF are similar by SAS Similarity Theorem.

Option (C) is correct .

Step-by-step explanation:

Definition of SAS Similarity property

Two triangles are said to be similar by SAS Similarity property If two sides are proportional and one corresponding angle congruent .

In △ABC and △DEF

\frac{ED}{AB}= \frac{7}{21}

\frac{ED}{AB}= \frac{1}{3}

and

\frac{EF}{BC}= \frac{11}{33}

\frac{EF}{BC}= \frac{1}{3}

Thus

\frac{ED}{AB}=\frac{EF}{BC}= \frac{1}{3}

∠ABC = ∠DEF  (As given in the figure )

Thus △ABC and △DEF are similar by SAS Similarity property .

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