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3 years ago

What is 2/5+5/3+9/3=

Mathematics

1 answer:

yuradex [85]3 years ago

7 0

The answer is 76/15. The answer can also be written as 5 1/15 or 5.06

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wolverine [178]

Answer:

1. slope

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4. y intercept

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6. it crosses the x axis

7. when the value of y is zero

8. when the form is y = something

9. when the form is x = something

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3 years ago

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

BartSMP [9]

Answer:

226 feet

Step-by-step explanation:

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3 years ago

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Use multiplication to write 2 + 2 + 2 +<br> 2+2.

Katena32 [7]

2 x 5
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2 x 5= 10

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3 years ago

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(3,4) and (12,19) find the equation of the line that passes through it

harina [27]

Answer:

The equation of the line will be:

$y=\frac{5}{3}x-1$

Step-by-step explanation:

Given the points

(3, 4)

(12, 9)

Finding the slope between (3, 4) and (12, 9)

$\left(x_1,\:y_1\right)=\left(3,\:4\right),\:\left(x_2,\:y_2\right)=\left(12,\:19\right)$

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{19-4}{12-3}$

$m=\frac{5}{3}$

The equation of the line can be obtained using the point-slope form of the equation of the line

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 5/9 and the point (3, 4)

$y-4=\frac{5}{3}\left(x-3\right)$

$y-4+4=\frac{5}{3}\left(x-3\right)+4$

$y=\frac{5}{3}x-1$

Therefore, the equation of the line will be:

$y=\frac{5}{3}x-1$

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3 years ago

Calculus: Help ASAP

wariber [46]

$\bf \displaystyle \int~\cfrac{sec^2(x)}{\sqrt{1+tan(x)}}\cdot dx\\\\
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u=1+tan(x)\implies \cfrac{du}{dx}=sec^2(x)\implies \cfrac{du}{sec^2(x)}=dx\\\\
-------------------------------\\\\
\displaystyle \int~\cfrac{\underline{sec^2(x)}}{\sqrt{u}}\cdot\cfrac{du}{\underline{sec^2(x)}}\implies \int~\cfrac{1}{\sqrt{u}}\cdot du\implies \int~u^{-\frac{1}{2}}\cdot du
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3 years ago

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