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2 years ago

Point A is in Quadrant II.

Mathematics

1 answer:

Digiron [165]2 years ago

7 0

Answer:

First quadrant

Step-by-step explanation:

A is reflected to the right over the x-axis

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Question 13

PtichkaEL [24]

Answer:

B. 30x

D. x(45-15)

Step-by-step explanation:

The distributive property lets you factor out the common factor of x. The sum of coefficients can be simplified to a single coefficient.

45x -15x = x(45 -15) = 30x

5 0

2 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

Factor to the given polynomial completely. 4x³+24x²-288x

STatiana [176]

Answer: $\Large\boxed{4x(x+12)(x-6)}$

Step-by-step explanation:

Given expression

4x³ + 24x² - 288x

Factorize 4x out from the expression

4x · x² + 4x · 6x - 4x · 72

4x (x² + 6x - 72)

Cross multiply to factorize the remaining polynomial expression

The meaning is to allow the factored product of the constant to add up to the first-degree term

x 12

x -6

Combine the result

$\Large\boxed{4x(x+12)(x-6)}$

Hope this helps!! :)

Please let me know if you have any questions

3 0

1 year ago

Read 2 more answers

Select the correct answer

Zepler [3.9K]

Answer:

number 3

Step-by-step explanation:

thats my calcue

7 0

2 years ago

Read 2 more answers

4. Which graph shows a non-proportional linear relationship between x and y? A. В.

Ghella [55]

Answer:

I think ( b) is non proportional linear

4 0

3 years ago