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MA_775_DIABLO [31]
3 years ago
11

Help!! what is the distance between points Q and S

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
6 0
6 units is the answer
Schach [20]3 years ago
3 0

Answer:

6 units

Step-by-step explanation:

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What is the product of z1 and z2 if
MaRussiya [10]

Answer:

308[cos(45) + isin(45)]

Step-by-step explanation:

z1×z2:

Modulus: r1 × r2

= 7×44 = 308

Argument: theta1 + theta2

= -70 + 115 = 45

z1z2 = 308[cos(45) + isin(45)]

Or

z1z2 = 154sqrt(2) + (i)154sqrt(2)

sqrt: square root

8 0
4 years ago
What is the equation of a line that is parallel to  −3x+4y=4 and passes through the point (4,0)?
Genrish500 [490]
So you have to first put put the equation in slope-intercept form.
-3x+4y=4
+3x      +3x
_______________
4y=4+3x
then you divide 4 by 4 and then divide 3x by 4 and you should get y=1+3/4x
then you plug in x and only x so that you can find y and then do the same once you find y 
y=1+ (4)3/4
y= 1+3
y=4
then plug in y and solve for x
4= 1+ 3/4x
subtract 1 from both sides
3=3/4x
divide both sides by 3/4
and x=4 
so then you find b and put it all in a equation.

3 0
3 years ago
CD is the perpendicular bisector AB. G is the midpoint of AB. points E and F lie on CD. which pair of line segments must be cong
Ugo [173]
AG and GB must be congruent and CG and GD must be congruent as well
6 0
3 years ago
Read 2 more answers
Cual es la. Longitud de un lápiz 2
asambeis [7]

<span>Traduje su pregunta al Inglés y respondió a esto. La longitud de un lápiz estándar número 2 es de 7,5 pulgadas, y el lápiz tiene un diámetro de unos 7 milímetros. Espero que esto ayudó☻</span>



I translated your question to english and answered this. <span>The length of a standard number 2 pencil is 7.5 inches, and the pencil has a diameter of about 7 millimeters. Hope this helped ☻

</span>
4 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
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