Ask question

Ask question

All categories

2 years ago

13

The depth of an underwater camera on a cable anchored to the sea floor is proportional to the time. The table records the time i

n seconds (s) and depth in meters (m) of the camera. What are the missing values in the table?

1 answer:

SOVA2 [1]2 years ago

4 0

Answer:

20=-1

60=-3

100=-5

240=-12

Step-by-step explanation:

divide time and depth by 20

You might be interested in

Square root of 15-x=-3+Square root of 2x+3<br><br> Solve for x

PSYCHO15rus [73]

$
\sqrt{15-x}=-3\sqrt{2x+3}\impliedby \textit{divide by -3}
\\ \quad \\
\cfrac{\sqrt{15-x}}{-3}=\sqrt{2x+3}\impliedby \textit{squares both sides}
\\ \quad \\
\left( \cfrac{\sqrt{15-x}}{-3} \right)^2=(\sqrt{2x+3})^2\implies 
\cfrac{(\sqrt{15-x})^2}{(-3)^2}=(\sqrt{2x+3})^2
\\ \quad \\
\cfrac{15-x}{9}=2x+3\impliedby \textit{multiply both sides by 9}
\\ \quad \\
15-x=18x+27\impliedby \textit{solve for "x"}$

5 0

3 years ago

Write an expression using all six trigonometric functions such that the value of the expression is 3

nlexa [21]

Take Sin of 5 and subtract Cos 2
Sin 5 Cos -2
5-2=3

5x+3=3

√x=3

2x+5y+(1)z=3

3 0

3 years ago

The number of 8th graders in choir is three times the number of the 7th graders. if there are 48 8th graders choir how.many 7th

stira [4]

Divide 48 by 3, for every three 8th graders, there is one 7th grader in choir
48÷3=16
There's 16 7th graders in choir !!

7 0

2 years ago

Please help me please

n200080 [17]

Answer:

Step-by-step explanation:

110_5

7 0

2 years ago

I don’t understand how to do this

schepotkina [342]

Answer:

The solution is $x =0.$

Step-by-step explanation:

The equation

$\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2$

can be rewritten as

$2* sin(\dfrac{3\pi }{2} +2) =-2$

and can be further simplified to

$sin(\dfrac{3\pi }{2}+x ) =-1$ .

Now, taking the inverse sine of both sides we get:

$sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)$

$\bold{(2).}\: \dfrac{3\pi }{2} +2 =sin^{-1}(-1)$

The value of the right side on the interval $[0,2\pi)$ is

$sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o)$ ,

which makes the equation (2)

$\dfrac{3\pi }{2}+x =\dfrac{3\pi}{2}$

solving for $x$ gives

$\boxed{x = 0}$

which is our solution.

4 0

2 years ago