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gtnhenbr [62]
3 years ago
10

A rectangle has vertices (-1, 1), (-4, 1), (-1, 3), and (-4, 3). If the

Mathematics
1 answer:
Cloud [144]3 years ago
4 0
(-4,8) is the answer
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BRAINLIESTTT ASAP!!! PLEASE HELP ME :)
loris [4]

Answer:

○ ³\⁷

Step-by-step explanation:

Since you are multiplying ⁷√x three times, you write it like this first, ⁷√x³, then according to one of the Six Exponential Rules, ⁿ√aᵐ = aᵐ\ⁿ, ⁷√x³ gets rewritten as x³\⁷.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**In one of my You-Tube videos, it talks about all six exponential rules. The video is titled "Six Exponential Rules". Go check it out and get as much assistance as you can from the tutorial.

4 0
3 years ago
Can someone help me with this question please
Whitepunk [10]
You know how there are 4 different areas in the graph, rotating it 180 degrees from that position will make it be in quadrant 2 (top left). in order to graph the ponts, since it is right across, then you just have to flip the shape around. like how you take a selfe, it flips the capture image around
3 0
3 years ago
Use compatible numbers to estimate the quotient 5,514÷82
Sphinxa [80]
The answer is 67 because 67 x 82 is 5,494 which us close to 5,514
5 0
3 years ago
Read 2 more answers
a company is offering a job with a salary of $30,000 for the first year and a 5% raise each year after that. if the 5% raise con
Ber [7]
<span>First year is 30,000.
</span><span>Earn 5% raise every year.
</span>Growth factor is 1.05 this sounds a lot like a geometric ratio.

An = A1 × r^(n-1)Sn = A1 × (1 - r^n) / (1-r)<span>n = 40
A1 = 30,000
A40 = $30,000 * 1.05^39 = $201,142.53

S40 = A1 * (1 - 1.05^40) / (1-1.05) which becomes:
S40 = 30,000 * -6.039988712 / -.05 which becomes: 
</span>S40 = -181,199.6614 / -.05 which becomes:
S40 = $3,623,993.227

<span>The individual yearly calculations are shown below: </span>

8 0
4 years ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
7nadin3 [17]

Correct answer is: distance from D to AB is 6cm

Solution:-

Let us assume E is the altitude drawn from D to AB.

Given that m∠ACB=120° and ABC is isosceles which means

m∠ABC=m∠BAC = \frac{180-120}{2}=30

And AC= BC

Let AC=BC=x

Then from ΔACD , cos(∠ACD) = \frac{DC}{AC} =\frac{4}{x}

Since DCB is a straight line m∠ACD+m∠ACB =180

                                              m∠ACD = 180-m∠ACB = 60

Hence cos(60)=\frac{4}{x}

          x=\frac{4}{cos60}= 8

Now let us consider ΔBDE, sin(∠DBE) = \frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}

DE = 12sin(30) = 6cm

7 0
4 years ago
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