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mr_godi [17]
3 years ago
15

Mr. Bennett is comtemplating which chauffeur car service to take to the airport the first cost 26$ up front and 1$ per mile the

second costs 11$ up front and 4$ per mile for certain driving distance,the two companies charge the same total fare. What is the total fare? What is the distance?
Mathematics
1 answer:
Over [174]3 years ago
3 0
I need to gain a point sorry but idk
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Walking path across the park is represented by the equation Y equals negative 2X -7. A new path will be built perpendicular to t
Genrish500 [490]

here the equation of path is -2x-7=y

let us find slope of this line by using y=mx+b

so slope m=-2

now new path is perpendicular to this path.

product of slopes of perpendiculars is -1

so slope of new path is 1/2

now it passes through (-2,-3) with slope 1/2

using y=mx+b to get value of b

-3=1/2(-2) +b

b=-2

plugging m=-1/2 and b=-2 in y=mx + b to get the final equation as

y=(-1/2) x -2 is the equation of new path

5 0
3 years ago
What is the temperature, in degrees Fahrenheit, shown on the thermometer to the nearest integer? Enter your integer answer in th
Illusion [34]
It’s negative 4 because the scale shows there is 4 lines
8 0
2 years ago
The sum of two rational numbers of 63, and their difference is 12? What are the numbers?
VladimirAG [237]

Answer:

The two numbers are 37.5 and 25.5

Step-by-step explanation:

Comment

Let the two numbers be x and y

Equations

x + y = 63

x - y =  12

Solution

Add the two equations. The ys cancel out.

2x = 75               Divide by 2

2x/2 = 75/3         Do the division

x = 37.5

Now use one of the given equations to solve for y

x + y = 63

x = 37.5

37.5 + y = 63                     Subtract 37.5 from both sides

37.5-37.5+y= 63 - 37.5     Collect the like terms on both sides

y = 25.5

Check

x - y =? 12

37.5-25.5 =? 12

12 = 12      

3 0
3 years ago
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
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The graph of f(x) and g(x) are shown below
Jlenok [28]

Answer:

c

Step-by-step explanation:

7 0
2 years ago
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