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Mumz [18]
4 years ago
13

The function F(x) = 6x-2/5 is an example of a rational function. A. True B. False

Mathematics
2 answers:
Anton [14]4 years ago
4 0
By definition, a rational function, is an algebraic expression that includes a term in fractional form containing polynomials. To illustrate more clearly, this is an example of a rational function: 

f(x)= \frac{ 3x^{2}+2 }{5 x^{3}+2x }

Basically, a rational function must have polynomials in both the numerator and denominator of the fractional term. Since the given function f(x)= 6x-2/5 only contains a polynomial on the numerator, this is not a rational function. The denominator is a constant, not a polynomial.

The answer is false.
BigorU [14]4 years ago
3 0
<span>The statement about "The function F(x) = 6x-2/5 is an example of a rational function." is false. The answer is letter B. The definition of a rational polynomial is that it is written in a form in which a polynomial is divided by a polynomial. Yes, 6x - 2 is a polynomial, a binomial to be precise but the 5 itself is not. It is not a polynomial, let alone a monomial because it does not contain a variable x or y. It is only a number. And so the statement is false.
</span>
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