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solniwko [45]
3 years ago
5

A rate that describes how much smaller or larger the scale drawing is than the real object

Mathematics
1 answer:
Paul [167]3 years ago
7 0
The answer is a scale factor
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Factorize 9(a+1)^2-81​
Lunna [17]

Answer:9a^2+18a-72

Step-by-step explanation:

9(a+1)^2-81

9(a+1)(a+1)-81

Open brackets

9(a^2+a+a+1)-81

9(a^2+2a+1)-81

9a^2+18a+9-81

9a^2+18a-72

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12/23<br> 19/34<br> 22/45<br> 8/41
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Why are you even asking, i'll edit the answer once I know.

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Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n
Nady [450]

The equation of f(x) = e^{-6x} by maclaurin series is f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}.

The maclaurin series for f(x) is defined by the following formula:

f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}--------------(1)

Where f^{i} is the i - th derivative of the function

If f(x) = e^{-6x}, then the formula of the i - th derivative of the function is:

f^{i} =(-6)^{i} .e^{-6x}----------------------(2)

Then,

f^{i}(0) = (-6)^{i}

Lastly, the equation of the trascendental function by Maclaurin series is: f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i}  }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}---------------(3)

Hence,

The equation of f(x) = e^{-6x} by maclaurin series is f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}.

Find out more information about maclaurin series here

brainly.com/question/24179531

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2 years ago
Lena has an envelope that is 3 inches tall. The envelope is 3 9/10 times as long as it is tall. How long is her envelope?
Kaylis [27]

Answer:

11.7 Inches

Step-by-step explanation:

9/10 is 0.9, so 3+0.9= 3.9

3.9 x 3 is 11.7 inches, or you can round it to 12 inches or a foot.

8 0
4 years ago
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